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Katyanochek1 [597]
2 years ago
8

Relly Need HELP IN THIS PLZ TELL ME THE ANSWER !!!!!!!!!!!!!!

Mathematics
1 answer:
jolli1 [7]2 years ago
7 0
Conner is correct because when 2 exponents with the same base are multiplied, you add the exponents (for example, (x^3)*(x^4) = (x^7)
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What's the square root of 1331 to the third power
ivanzaharov [21]

Answer:

48559 if to the nearest whole number

48558.7 if to the nearest tenth

8 0
2 years ago
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Let f(x) = x^2 − 5. Find f(-3)
Art [367]

Answer:

f(-3)=4

Step-by-step explanation:

Substitute x=-3 into the function

f(-3)=(-3)^2-5

f(-3)=9-5

f(-3)=4

5 0
2 years ago
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Find the equation of the line perpendicular to 3x-7y=42 which passes through the point (-3,-8)
harkovskaia [24]
For perpendicular lines, m1m2 = -1 or m2 = -1/m1; where m1 and m2 are the slopes of the lines.
Here line 1 is 3x - 7y = 42
7y = 3x - 42
y = 3/7 x - 6; Hence m1 = 3/7
m2 = -1/(3/7) = -7/3
Required equation y - y1 = m2(x - x1)
y - (-8) = -7/3(x - (-3))
y + 8 = -7/3(x + 3)
y + 8 = -7/3 x - 7
y = -7/3 x - 7 - 8
y = -7/3 x - 15
4 0
3 years ago
If f(x) = x + 6, g(x) = 3x and h(x) = 10/x , find the value of f^-1(g(h(5))).
NNADVOKAT [17]
Start from inside to the out side of the function;
h(5)=10/5=2
g(h)=g(2)=3*2=6
now, get the f inverse of x;
f(x)=y=x+6
x=y-6
replace x with y and y with x
y=x-6
so f^-1= x-6
so f^-1(g)=f^-1(6)=6-6=0
I am not sure only of the last value, but pretty sure of the rest.
3 0
3 years ago
BRAINLIEST IF CORRECT!:)) PLEASE SHOW WORK!! <br><br> Here is the attachment below.:) &lt;----
kipiarov [429]
Please find the solution below.. If you have questions, let me know.

6 0
3 years ago
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