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Sliva [168]
3 years ago
7

Clare has 80 pencils and 56 erasers to give away. What is the largest number of group that can formed with the same numbers of p

encils and erasers in each group?
Mathematics
1 answer:
Leokris [45]3 years ago
6 0

Answer:

56

Step-by-step explanation:

I assume each person in the group must have 1 pencil AND 1 eraser each.

Since you have more pencils than erasers, then the limiting factor is the number of erasers. So a group of 56 people will have 1 pencil And 1 eraser and Clare will have 24 pencils left over (assuming Clare has her own pencil and eraser - if not then the group size is 55 assuming Clare is not in the group)

sorry if it's too confusing

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3x = -y + 12<br> 2x + 3y = -6
tangare [24]

Answer:

3x=-y+12

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collecting the like terms we have

3x+y=12

2x+3y=-6

to solve this simultaneous equation, we use substitution method

we make y the subject in equation one:

y=12-3x

then we put y=12-3x into 2x-3y=-6 in equation two

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2x+36-9x=-6

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x=-42÷-7

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y=12-3(6)

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3 0
3 years ago
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katrin [286]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
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Slav-nsk [51]
If you would like to solve the following proportion 15 / 21 = 5 / x, you can do this as follows:

15 / 21 = 5 / x       /*x
15 / 21 * x = 5      /*21
15 * x = 5 * 21      /15
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3 0
3 years ago
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kondaur [170]

Answer:

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Step-by-step explanation:

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Evgesh-ka [11]

Answer:

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Step-by-step explanation:

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Sorry, if I did wrong, I'm in middle school so its a bit ahrd.

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