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Sliva [168]
3 years ago
7

Clare has 80 pencils and 56 erasers to give away. What is the largest number of group that can formed with the same numbers of p

encils and erasers in each group?
Mathematics
1 answer:
Leokris [45]3 years ago
6 0

Answer:

56

Step-by-step explanation:

I assume each person in the group must have 1 pencil AND 1 eraser each.

Since you have more pencils than erasers, then the limiting factor is the number of erasers. So a group of 56 people will have 1 pencil And 1 eraser and Clare will have 24 pencils left over (assuming Clare has her own pencil and eraser - if not then the group size is 55 assuming Clare is not in the group)

sorry if it's too confusing

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Given the isosceles trapezoid below, find AG.<br> Show all the work
Dmitry [639]

We know the width of the rectangle in the middle of the trapezoid is 24 (from the top of the image), so we can subtract that from the bottom width of the trapezoid to get the combined length of the bottom of both triangles.

40 - 24 = 16

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Studentka2010 [4]

Hello from MrBillDoesMath!

Answer:

x = ( -9 + sqrt(33) ) /4

and

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Using the quadratic formula with a = 2, b = 9 and c = 6 gives

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Answer:

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Step-by-step explanation:

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Assuming it's length is 4 m.

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24 m

Now what you'd do is substitute your values for my assumed values.. Cheers

6 0
3 years ago
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