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dybincka [34]
3 years ago
15

A quantity representing how many times the base is multiplied by itself

Mathematics
1 answer:
ankoles [38]3 years ago
4 0

Answer:

Let suppose the quantity be x^{y} where x=Base, y=exponent

Now, if the base is multiplied by itself

i.e , x \times x=x^{2}

If we raise the power of base multiply by itself by y/2, then it becomes equal to the quantity given.

[x^{2}]^{\frac{y}{2}}=x^{y}=Quantity

Or if we raise the power of quantity by 2/y , then it becomes equal to base multiply by itself.

[x^{y}]^{\frac{2}{y}}= x^{2}

Quantity=x^{y}=[base\times base]^{\frac{y}{2}}=[x^{2}]^{\frac{y}{2}}




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Which of the following sequences is an arithmetic sequence?
Elza [17]

Answer:

The answer is C

Step-by-step explanation:

The only equation that you are adding n of each time. In this scenario n=3

4 0
3 years ago
Students who attend Washington Middle School are either in seventh or eighth grade. At the end of the first semester 25% of the
Irina18 [472]

Answer:

There are <u>1240</u> students who attended Washington Middle School.

Step-by-step explanation:

Given:

Students who attend Washington Middle School are either in seventh or eighth grade.

At the end of the first semester 25% of the students at Washington Middle School were on the honor roll.

Seventh graders represented 60% of the students on the honor roll.

If 124 students on the honor roll were in eighth grade.

Now, to find the students attend Washington Middle School.

Let the total number of students be x.

So, the students at Washington Middle School were on the honor roll:

<u><em>25% of </em></u>x<u><em /></u>

=\frac{25}{100} \times x

=\frac{25x}{100}

=\frac{x}{4}

As, given seventh graders represented 60% of the students.

So, the students on the honor roll represented as seventh graders:

60\%\ of\ \frac{x}{4}

=\frac{60}{100} \times \frac{x}{4}

=0.6\times \frac{x}{4}

=\frac{0.6x}{4}

As, 124 students on the honor roll were in eighth graders.

Thus,

According to question:

\frac{x}{4} -\frac{0.6x}{4} =124

\frac{x-0.6x}{4} =124

\frac{0.4x}{4} =124

<em>Multiplying both sides by 4 we get:</em>

0.4x=496

<em>Dividing both sides by 0.4 we get:</em>

x=1240.

Therefore, there are 1240 students who attended Washington Middle School.

6 0
4 years ago
What is the ratio of the area of sector ABC to the area of sector DBE?
shusha [124]

We have to find the" ratio of the area of sector ABC to the area of sector DBE".

Now,

the general formula for the area of sector is

Area of sector= 1/2 r²θ

where r is the radius and θ is the central angle in radian.


180°= π rad

1° = π/180 rad


For sector ABC, area= 1/2 (2r)²(β°)

= 1/2 *4r²*(π/180 β)

= 2r²(π/180 β)

For sector DBE, area= 1/2 (r)²(3β°)

= 1/2 *r²*3(π/180 β)

= 3/2 r²(π/180 β)

Now ratio,

Area of sector ABC/Area of sector DBE =\frac{2r^{2}*\ \frac{\pi}{180} beta}{3/2 r^{2}*\ \frac{\pi}{180}beta}

= 4/3

7 0
4 years ago
Read 2 more answers
Find the missing side. Write as an exact answer in simplest radical form.
Eddi Din [679]

Answer:

b = 36

Step-by-step explanation:

Assuming this is a right triangle with hypotenuse = c and legs a and b

Then using Pythagoras' identity.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

a² + b² = c², and substituting values

15² + b² = 39², that is

225 + b² = 1521 ( subtract 225 from both sides )

b² = 1296 ( take the square root of both sides )

b = \sqrt{1296} = 36

7 0
4 years ago
Simplify each expression. Write your answer as a complex number.<br> (41) + (2 +81)
maw [93]
(41)+(83) is the answer
5 0
4 years ago
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