8.7/2=q/4
multiply both sides by 4: q=8.7/2*4
multiply both sides by 2: 2q=8.7 times 4
refine the equation: 2q=34.8
multiply both sides by 10: 20q=348
Divide both sides by 20: 20q/20=348/20
refine the equation for the final answer: q=87/5
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Answer:
<u>Fred.</u>
Started hang gliding at a height of 700 ft and descends 15 feet every seconds
<u>Gene</u>
Started hang gliding at a height of 575 ft and descends 10 feet every seconds
Step-by-step explanation:
The function that models Fred's hang gliding is 
The initial value is 700 feet. This Fred was 700 feet above see level before he starts descending.
The rate of descent is -15 ft/s. This means Fred descends 15 feet in one second.
From the table the initial height is 575 ft. This means Gene was 575 feet above sea-level at the beginning of the hang gliding.
The rate of descent is
ft/s.
This means that in every seconds, Gene descends 10 feet.
Answer:
<h3>1 secs</h3>
Step-by-step explanation:
Given the height of the discus can be modeled by the equation y=−16x
^2
+32x+4, where y represents the height in feet of the discus in seconds, the velocity of the discus at its maximum height is zero.
Velocity v = dy/dx = 0
dy/dx = -32x + 32
0 = -32x + 32
32x = 32
x = 1 secs
Hence it will take the discus 1 secs to reach its maximum height
I believe the answer will be 23in