All categories

2 years ago

What is the remainder when x+ - 2x2 – 3x – 7 is divided by x + 2?

Mathematics

1 answer:

guapka [62]2 years ago

4 0

x+-2*2-3x-7

x+4-3x-7

x+1.x-7

x.x-7

2x-7

You might be interested in

Carter rewrites 28 × 2 in expanded form to find the product. 28 × 2 = (20 × 2) + (8 × 2) What is the next step to find the produ

earnstyle [38]

Answer:

add the product of 20×2 to the product of 8×2

Step-by-step explanation:

that will give u 40+ 16 Which is equal to 56

5 0

2 years ago

Read 2 more answers

What is 61/4 as a decimal

Aloiza [94]

Answer:

15.25

Step-by-step explanation:

Divide 61 by 4 to get 15.25.

This is your answer.

6 0

2 years ago

Write the number in standard notation. 4.16 *10^-5 0.00000416 0.0000416 0.000416 –208

zalisa [80]

$4.16\cdot10^{-5}\\\\move\ the\ decimal\ 5\ place\ left\\\\4.16\cdot10^{-5}=0.0000416$

4 0

2 years ago

A sink has two faucets: one for hot water and one for cold water. The sink can be filled by a cold water faucet in 3 minutes. If

iragen [17]

Answer: $6\ minutes$

Step-by-step explanation:

You can use the following formula:

$\frac{T}{A}+\frac{T}{B}=1$

You can say that "T" is the time (in minutes) for both faucets working together, "A" is the time (in minutes) for cold water faucet working alone and "B" is the time (in minutes) for hot water faucet working alone.

Based on the data given in the exercise, you can identify that:

$T=2\\A=3$

Therefore, substituting these values into the formula and solving for "B", you get that this is:

$\frac{2}{3}+\frac{2}{B}=1\\\\\frac{2}{B}=1-\frac{2}{3}\\\\\frac{2}{B}=\frac{1}{3}\\\\2=\frac{1}{3}B\\\\2*3=B\\\\B=6$

3 0

2 years ago

Given the function f(x)=x^2-8x+13f(x)=x, determine the average rate of change of the function over the interval −1≤x≤6.

Ann [662]

Given:

Consider the given function is:

$f(x)=x^2-8x+13$

To find:

The average rate of change of the function over the interval $-1\leq x\leq 6$ .

Solution:

The average rate of change of the function f(x) over the interval [a,b] is:

$m=\dfrac{f(x_2)-f(x_1)}{x_2-x_1}$

We have,

$f(x)=x^2-8x+13$

At $x=-1$ ,

$f(-1)=(-1)^2-8(-1)+13$

$f(-1)=1+8+13$

$f(-1)=22$

At $x=6$ ,

$f(6)=(6)^2-8(6)+13$

$f(6)=36-48+13$

$f(6)=1$

Now, the average rate of change of the function f(x) over the interval $-1\leq x\leq 6$ is:

$m=\dfrac{f(6)-f(-1)}{6-(-1)}$

$m=\dfrac{1-22}{7}$

$m=\dfrac{-21}{7}$

$m=-3$

Therefore, the average rate of change of the function f(x) over the interval $-1\leq x\leq 6$ is -3.

6 0

2 years ago