Answer:
Form: 2^7, 2^7 = 128
Step-by-step explanation:
You cannot multiply exponent, you must add the exponents.
4 + 3 = 7.
Keep the base the same.
Then find what 2^7 is.
Multiply:
2 x 2 x 2 x 2 x 2 x 2 x 2.
2 x 2 =
4 x 2 =
8 x 2 =
16 x 2 =
32 x 2 =
64 x 2 =
128.
Answer:
1. m∠B=110°
2. 560 cm3
3. Numerical data
4. 2000 cm3
5. 50%
Step-by-step explanation:
1. The explanation of part 1 is given in the attachment.
2. Given dimensions : 10 cm, 8 cm, and 7 cm.
Let Length of cuboid =10 cm
breadth/width of cuboid =8 cm
height of cuboid = 7cm
Volume of cuboid = length *width* height
=( 10 *8*7) cm3
=(560) cm3
3. Age, Birth date and weight are the types/examples of "<u>Numerical Data"</u> because these all are describe in terms of numeric values.
4. 1 liter = 1000 cm3 or 1 cm3 = 0.001 liter
1.5 liters =(1.5*1000) cm3 = (15*100) =1500 cm3
1 dm3 =1000 cm3
0.35 dm3 = (0.35*1000) cm3 = (35*10) cm3 =350 cm3
Given expression: 1.5 litre + 0.35 dm3 + 150 cm3 = <u> </u> cm3
1500 cm3 + 350 cm3 +150 cm3 = <u>2000</u> cm3
5. If A=(1/2)B, then B : A = <u>50</u> %
Ratio: B : A
B : (1/2) B
1: (1/2)
50 % (The value of A is half of the value of B)
First question
Volume = height * radius*radius*3.14
5*3*3*3.14 = 141.3 in3
Second qustion
Violume = height * radius * radius * 3.14
28*8*8*3.14= 5626.88 cm3
So the answer is 1875.63 because it's the closest
Answer:
•A c-chart is the appropriate control chart
• c' = 8.5
• Control limits, CL = 8.5
Lower control limits, LCL = 0
Upper control limits, UCL = 17.25
Step-by-step explanation:
A c chart is a quality control chart used for the number of flaws per unit.
Given:
Past inspection data:
Number of units= 100
Total flaws = 850
We now have:
c' = 850/100
= 8.5
Where CL = c' = 8.5
For control limits, we have:
CL = c'
UCL = c' + 3√c'
LCL = c' - 3√c'
The CL stands for the normal control limit, while the UCL and LCL are the upper and lower control limits respectively
Calculating the various control limits we have:
CL = c'
CL = 8.5
UCL = 8.5 + 3√8.5
= 17.25
LCL = 8.5 - 3√8.5
= -0.25
A negative LCL tend to be 0. Therefore,
LCL = 0
C. \: x = 2 \: or \: x = 3
