Ask question

Ask question

All categories

Bad White [126]

3 years ago

9

During a construction project, heavy rain filled construction cones with water. The diameter of a cone is 12 in. and the height

is 27 in.
What is the volume of the water that filled one cone?
Enter your answer as a decimal in the box. Use 3.14 for pi.

in³

1 answer:

sergey [27]3 years ago

3 0

Volume of a cone = <span>πr^2(h/3)
r=6
h=27

v = </span><span>π(6^2)27/3
v = </span><span>π (36)(9)

v=</span><span>π324 in. cubed
or
v=1,017.36 in. cubed </span>

You might be interested in

Benny made a scale drawing of his bedroom what is the area of his actual bedroom

Mama L [17]

40 inches srry if im wrong

7 0

3 years ago

Read 2 more answers

HELP ME WITH THIS QUESTION PLEASE

lara [203]

Answer:

0.79

Step-by-step explanation:

all you really need to do is multiply your decimal (15.8) by your percent (5) so, you problem would look like 15.8(.05) (note it is .<em>0</em>5 because there need to be 2 decimal places) so, your answer is .79

6 0

3 years ago

Plz help!! Me with this question

kramer

Answer: 3/4

Step-by-step explanation: 12/16 which simplifies to 3/4.

4 0

2 years ago

Read 2 more answers

21. 3x + 4 = x2<br> How would I solve this using the quadratic equation

hodyreva [135]

Answer:

old

Step-by-step explanation:

idk because I'm just to pit down this because we haven't learned this yet

4 0

2 years ago

M is the midpoint of AN, A has coordinates

maksim [4K]

Step-by-step explanation:

According to Question , M is the midpoint of AN, A has coordinates (-7,4), and M has coordinates (-4, -1).

<u>Figure</u><u> </u><u>:</u><u>-</u>

$\setlength{\unitlength}{1 cm}\begin{picture}(20,12) \put(4,0.2){\line(0,-1){0.4}}\put(1,0){\line(1,0){6}} \put(3.8,-0.6){$\bf M(-4,-1) $} \put(1,-0.6){$\bf A (-7,4)$} \put(6.8,-0.6){$\bf N(x,y)$} \end{picture}$

Let the coordinates of N be ( x , y )

Now , according to Midpoint Formula , the midpoint of points say A(x , y) and B (x' , y') is given by ,

$\boxed{\blue{ \bf Midpoint =\bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg) }}$

<u>On</u><u> </u><u>using</u><u> </u><u>this</u><u> </u><u>formula</u><u> </u><u>,</u><u> </u>

$=> Midpoint = \bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg) \\ \\ => (-4, 1) = \bigg( \dfrac{x -7 }{2} , \dfrac{y + 4 }{2}\bigg) \\ \\ => -4 = \dfrac{x-7}{2} \\\\ => x - 7 = -8 \\\\ => x = 7 -8 \\\\ \boxed{\red{\sf=> x = -1 }} \\\\ => \dfrac{y+4}{2}=-1 \\\\=> y +4 = -2 \\ \\ y = -4-2 \\\\\boxed{\red{\sf=> y = -6 }}$

8 0

2 years ago

Read 2 more answers