Answer:
C
Step-by-step explanation:
Write 8 and 512 as powers of 2:
![8=2^3](https://tex.z-dn.net/?f=8%3D2%5E3)
![512=2^9=(2^3)^3](https://tex.z-dn.net/?f=512%3D2%5E9%3D%282%5E3%29%5E3)
So we have
![\log_8512=\log_{2^3}(2^3)^3=3\log_{2^3}2^3=3](https://tex.z-dn.net/?f=%5Clog_8512%3D%5Clog_%7B2%5E3%7D%282%5E3%29%5E3%3D3%5Clog_%7B2%5E3%7D2%5E3%3D3)
Answer: 945.95
Step-by-step explanation:
If the equation is
then the domain is the set of all real numbers.
We can replace x with any real number and compute to get some real number output for y. There are no division by zero restrictions to worry about, or issues with taking a square root of a negative number (since this isn't really a square root function).
The cube root of a negative number is negative. For example,
because (-4)^3 = (-4)*(-4)*(-4) = -64.
In interval notation, the domain would be written as
to indicate the entire real number line.