Let x be the 1st odd number, and x+2 the second odd consecutive number:
(x)(x + 2) = 6[((x) + (x+2)] -1
x² + 2x = 6(2x + 2) - 1
x² + 2x = 12x +12 - 1
And x² - 10x - 11=0
Solve this quadratic expression:
x' = [+10 +√(10²- 4.(1)(-11)]/2 and x" = [+10 -√(10²- 4.(1)(-11)]/2
x' = [10 + √144]/2 and x" = [10 - √64]/2
x' = (10+12)/2 and x" = (10-12)/2
x = 11 and x = -1
We have 2 solutions that satisfy the problem:
1st for x = 11, the numbers at 11 and 13
2nd for x = - 1 , the numbers are -1 and +1
If you plug each one in the original equation :(x)(x + 2) = 6[((x) + (x+2)] -1
you will find that both generates an equlity
For a variable to vary directly to another is telling you to set up a proportion
v/g = v/g
36/4 = v/11
4v = 396
v = 99
6 -they lost that many
they won this many 6 plus this many 6
666
Well, since you didn't attach the options. I will try to simplify the problem for you.⬇
Problem➡8/9 ÷2/3
~How to solve it ⬇
8(3) / 9(2) = 24/18
So, that means that your answer might have to be
1 1/3~
Answer:
$27
Step-by-step explanation:
In this question, we are asked to calculate how much spent on some number of students in a bookstore where books were being signed by an author. We proceed as follows:
To calculate the amount she budgeted, there are different approach we can take. We can calculate the amount she has to pay for the signing at the old price. Then, we calculate the amount of money she has to pay on discounting the fees. We then subtract the values to arrive at the total value she has spent.
Firstly, we calculate the total amount of money to be spent on the students based on his budget. He had budgeted 1.15, then the total amount budgeted would be 30 * 1.15 = $34.5
Now we are made to know that she spent 0.25 less. Thus, the total amount spent less would be 30 * 0.25 = $7.5
The actual amount thus spent is $34.5 - $7.5 = $27
He spent a total of $27 on 30 students
