Find the angle between the given vectors to the nearest tenth of a degree.

kipiarov [429]

Hi!

Remember that an x-intercept is a point in which the line touches the x-axis (the horizontal line). And, the y-intercept is a point in which the line touches the y-axis (the vertical/up and down line)

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For A)

The coordinate of the y-intercept is (0,1)

The coordinate of the x-intercept is (3,0)

For B)

The coordinate of the y-intercept is (0,0)

The coordinate of the x-intercept is (0,0) !

*both the x and y axis meet at the origin. So, a line that goes through the origin (0,0) is intersecting with BOTH the x and y-axis.

Hope I helped! Comment if you have any questions or concerns.

-Gabby5792

5 0

3 years ago

What is the slope of the line that goes through (-5,5) and (5,-7)

sladkih [1.3K]

Answer:

-1/5

Step-by-step explanation:

slope formula:

m = y₂ - y₁ / x₂ - x₁

Two points are given:

(-5, -5) (5, -7)

m = -7 - (-5) / 5 - (-5)

m = -2 / 10

m = -1/5

7 0

3 years ago

Read 2 more answers

The heights of women aged 20 to 29 follow approximately the N(64, 2.82) distribution. Men the same age have heights distributed

ivann1987 [24]

Answer:96.97

Step-by-step explanation:

Given

mean height of women $\mu _w=64$

Standard deviation of height $\sigma _w=2.82$

mean height of men $\mu _=69.3$

Standard deviation of height $\sigma _m=2.71$

P $\left ( X$

P $\left ( \frac{x-\mu _w}{\sigma _w}\right )$

P $\left ( Z$

i.e. 0.9697=96.97 %

4 0

3 years ago

Let f(x)=5x+2 and gx=x^2-4x+1<br><br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bf%7D%7Bg%7D%285%29" id="TexFormula1" title="\f

Rasek [7]

Answer:

find f(5) and g(5) then divide f(5) by g(5) i.e f(5)/g(5) Answer will be 25/6

3 0

3 years ago

Genetic Defects Data indicate that a particular genetic defect occurs in of every children. The records of a medical clinic show

Dovator [93]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The probability that there exist 60 or more defected children is $P(x \ge 60)=0.0901$

Looking at the value for this probability we see that it is not so small to the point that the observation of this kind would be a rare occurrence

Step-by-step explanation:

From the question we are told that

in every 1000 children a particular genetic defect occurs to 1

The number of sample selected is $n= 50,000$

The probability of observing the defect is mathematically evaluated as

$p = \frac{1}{1000}$

$= 0.001$

The probability of not observing the defect is mathematically evaluated as

$q = 1-p$

$= 1-0.001$

$= 0.999$

The mean of this probability is mathematically represented as

$\mu = np$

Substituting values

$\mu = 50000*0.001$

$= 50$

The standard deviation of this probability is mathematically represented as

$\sigma = \sqrt{npq}$

Substituting values

$= \sqrt{50000 * 0.001 * 0.999}$

$= \sqrt{49.95}$

$= 7.07$

the probability of detecting $x \ge60$ defects can be represented in as normal distribution like

$P(x \ge 60)$

in standardizing the normal distribution the normal area used to approximate $P(x \ge 60)$ is the right of 59.5 instead of 60 because x= 60 is part of the observation

The z -score is obtained mathematically as

$z = \frac{x-\mu }{\sigma }$

$= \frac{59.5 - 50 }{7.07}$

$=1.34$

The area to the left of z = 1.35 on the standardized normal distribution curve is 0.9099 obtained from the z-table shown z value to the left of the standardized normal curve

Note: We are looking for the area to the right i.e 60 or more

The total area under the curve is 1

So

$P(x \ge 60) \approx P(z > 1.34)$

$= 1-P(z \le 1.34)$

$=1-0.9099$

$=0.0901$

3 0

3 years ago