Step-by-step explanation:
no, no, you use the equation to identify a, b and c.
then you use the formula with these values to get the solutions to the equation (the values of x for which the equation delivers 0).
always remember, a quadratic equation always has 2 solutions. sometimes at least one of them are not a real number, sometimes the 2 springs are equal, ...
x² - 4x - 2 = 0
a, b, c are the factors of the terms in x and the constant term.
so,
a = 1
b = -4
c = -2
x = (-b ± sqrt(b² - 4ac))/(2a)
x = (4 ± sqrt((-4)² - 4×1×-2))/(2×1) =
= (4 ± sqrt(16 + 8))/2 = (4 ± sqrt(24))/2 =
= (4 ± sqrt(4×6))/2 = (4 ± 2×sqrt(6)) / 2 =
= 2 ± sqrt(6)
x1 = 2 + sqrt(6)
x2 = 2 - sqrt(6)
Answer:
Answer is the 2nd one.
Step-by-step explanation:
Step-by-step explanation:
yes your answer is correct it's C
Answer:
40
Step-by-step explanation:
Answer:
y -11 = -2(x+4)
or
y = -2x+3
Step-by-step explanation:
We can use the point slope form of a line
y - y1 = m(x-x1) where m is the slope and (x1 ,y1) is a point on the line
y - 11 = -2(x- -4)
y -11 = -2(x+4)
We can rewrite it in slope intercept form
y-11 = -2x-8
Add 11 to each side
y = -2x+3
