Answer: A. A=(1000-2w)*w B. 250 feet
C. 125 000 square feet
Step-by-step explanation:
The area of rectangular is A=l*w (1)
From another hand the length of the fence is 2*w+l=1000 (2)
L is not multiplied by 2, because the opposite side of the l is the barn,- we don't need in fence on that side.
Express l from (2):
l=1000-2w
Substitude l in (1) by 1000-2w
A=(1000-2w)*w (3) ( Part A. is done !)
Part B.
To find the width w (Wmax) that corresponds to max of area A we have to dind the roots of equation (1000-2w)w=0 ( we get it from (3))
w1=0 1000-2*w2=0
w2=500
Wmax= (w1+w2)/2=(0+500)/2=250 feet
The width that maximize area A is Wmax=250 feet
Part C. Using (3) and the value of Wmax=250 we can write the following:
A(Wmax)=250*(1000-2*250)=250*500=125 000 square feets
Answer:
A system of linear equation could only have 1 solution. This is because the straight lines will only have to meet, cross, or intersect each other once.
A system of linear equation could only have 1 solution. This is because the straight lines will only have to meet, cross, or intersect each other once.
There are many different methods in arriving to the final answer. However, errors cannot be perfectly avoided. One of these errors to mistakenly identify equations as linear. It is important that we know that the equations we are dealing with are of exact or correct characteristics.
Also, if she had used substitution method, she might have mistakenly taken the value of one variable for the other.
Answer:
the answer is 66.205
Step-by-step explanation:
basically you look at the place value so
66.21 is basically the same as 66.210 then you look at the lowest number that can round UP to 66.210 which would be out of 1 to 9 would be 5 so the smallest number that can round up to 66.210 is 66.205 hope this helped :D
<em>PQR with vertices P(–2, 9), Q(7, –3), and R(–2, –3)</em>
<em>first distance P(–2, 9), Q(7, –3) </em>
<em>The distance (d) between two points is given by the following formula: </em>
<em>Answer= 15</em>
Answer:
a) h'(t)= (6cos3t,-9sin3t,3![\sqrt[]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B5%7D)
cos3t)
b) t=0.93994736+πn/3
c) Magnitude of h(t) is 3 which is a constant, so h(t) lies on a sphere
Step-by-step explanation:
