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4 years ago

12

Can someone explain to me how to solve inequalities with variables on both sides

1 answer:

Stolb23 [73]4 years ago

5 0

First, apply the distributive property to the left side of the inequality. Multiply each of the two numbers inside the parentheses by 6 and then add those products. Next, subtract -24 from both sides. Then, to get \begin{align*}x\end{align*} by itself on one side of the inequality, you need to divide both sides by 6.

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From the sum of 4a + b + c and 9a - c subtract the sum of 18a - b - c and 14a - 2b - c

sergiy2304 [10]

1:-

$\\ \rm\Rrightarrow 4a+b+c+9a-c$

$\\ \rm\Rrightarrow 4a+9a+b+c-c$

$\\ \rm\Rrightarrow 13a+b$

2:-

$\\ \rm\Rrightarrow 18a-b-c-(14a-2b-c)$

$\\ \rm\Rrightarrow 18a-b-c-14a+2b+c$

$\\ \rm\Rrightarrow 18a-14a-b+2b-c+c$

$\\ \rm\Rrightarrow 4a+b$

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3 years ago

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4 years ago

Solve for x: 7x + 15 = 38

oksano4ka [1.4K]

All you do is move all the terms that don't contain " x " to the right side and solve.

x = $\frac{23}{7}$

Hope that helps, Good luck! (:

8 0

3 years ago

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Solve each equation.<br> 1. x+6=4<br> 2.x- -4 = -6<br> 3.2(x-1)=-200<br> 4.2x+-3=-23

ziro4ka [17]

Step-by-step explanation:

1) x+6 =4

x. =4-6

x. =-2

2) x-(-4) =-6

x+ 4. =-6

x. =-6-4

x. =-10

3)2(x-1)=-200

2x-2 =-200

2x. = -200+2

2x. = -198

x. = -198/2

x. = -99

4)2x+(-3) =-23

2x-3. =-23

2x. =-23+3

2x. =-20

x. =-20/2

x. = -10

3 0

2 years ago

Solve the value of Z 8 = 16

dezoksy [38]

Answer:

Z=2

Step-by-step explanation:

Z8=16

Z=16/8

Z=2

4 0

3 years ago