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grandymaker [24]
3 years ago
12

I have a pile of 20 coins that includes dimes and quarters. The coins total is $2.75. How many quarters do I have?

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
5 0
You have 5 quarters which equals 25 cents each. Which in total comes to $1.25.
You have 15 dimes which is worth 10 cents each.
Which in total comes to $1.50.
$1.50
+$1.25
=$2.75
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Answer:

Option a)

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\lim_{x\to\\2}\frac{x^3}{(x-2)^4} \\\\\\lim_{x\to\\2}\frac{2^3}{(2-2)^4}\\\\\lim_{x\to\\2}\frac{2^3}{(0)^4} = \infty

Then. x = 2 it's a vertical asintota.

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if \lim_{x \to \infty}\frac{x^3}{(x-2)^4} = b then y = b is horizontal asymptote

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\lim_{x \to \infty}\frac{x^3}{(x-2)^4} \\\\\\lim_{x \to \infty}\frac{1}{(\infty)} = 0

Therefore y = 0 is a horizontal asymptote of f(x).

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3 years ago
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See attached picture.
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