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grandymaker [24]
3 years ago
12

I have a pile of 20 coins that includes dimes and quarters. The coins total is $2.75. How many quarters do I have?

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
5 0
You have 5 quarters which equals 25 cents each. Which in total comes to $1.25.
You have 15 dimes which is worth 10 cents each.
Which in total comes to $1.50.
$1.50
+$1.25
=$2.75
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Oksana_A [137]

Answer: 300 square feet  

Step-by-step explanation:

length of walkway = 20 + 2x

width of walkway = 15 + 2x

A(x) = (20 + 2x)(15 + 2x)

A(x) = 300 + 30x + 40x + 4x2

A(x) = 300 + 70x + 4x2

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If there are 48 boys and 32 girls what are all of the possible ratios
azamat

Answer:

48 to 32  8 to 4 4 to 2 24 to 16

Step-by-step explanation:

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How many solutions does this equation have?<br> 8−2(n+3)=n+7−3n
svp [43]
8-2(n+3)=n+7-3n

We move all terms to the left:

8-2(n+3)-(n+7-3n)=0

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-2(n+3)-(-2n+7)+8=0

We multiply parentheses

-2n-(-2n+7)-6+8=0

We get rid of parentheses

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We add all the numbers together, and all the variables

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6 0
3 years ago
The equation y = \large 1\frac{1}{2}x represents the number of cups of dried fruit, y, needed to make x pounds of granola. Deter
Natasha2012 [34]

Answer:

(1\frac{1}{2},1) - False

(4,6) - True

(18,12) -- False

(0,0) -- True

(2\frac{1}{2},3\frac{3}{4}) -- True

Step-by-step explanation:

The points are

(1\frac{1}{2},1) , (4,6), (18,12), (0,0) and (2\frac{1}{2},3\frac{3}{4}) ---- missing from the question

Given

y = 1\frac{1}{2}x

Required

Determine if each of the points would be on y = 1\frac{1}{2}x

To do this, we simply substitute the value of x and of each point in y = 1\frac{1}{2}x.

(a) (1\frac{1}{2},1)

In this case;

x = 1\frac{1}{2} and y = 1

y = 1\frac{1}{2}x becomes

y = 1\frac{1}{2} * 1\frac{1}{2}

y = \frac{3}{2} * \frac{3}{2}

y = \frac{9}{4}

y = 2\frac{1}{4}

<em>The point </em>(1\frac{1}{2},1)<em>  won't be on the graph because the corresponding value of y for </em>x = 1\frac{1}{2}<em> is </em>y = 2\frac{1}{4}<em></em>

(b) (4,6)

In this case;

x = 4

y = 6

y = 1\frac{1}{2}x becomes

y = 1\frac{1}{2} * 4

y = \frac{3}{2} * 4

y = \frac{3* 4}{2}

y = \frac{12}{2}

y = 6

<em>The point </em>(4,6)<em>  would be on the graph because the corresponding value of y for </em>x = 4 is y = 6

(c) (18,12)

In this case:

x = 18;y = 12

y = 1\frac{1}{2}x becomes

y = 1\frac{1}{2} * 18

y = \frac{3}{2} * 18

y = \frac{3* 18}{2}

y = \frac{54}{2}

y = 27

<em>The point </em>(18,12)<em>  wouldn't be on the graph because the corresponding value of y for </em>x = 18<em> is </em>y = 12<em></em>

(d) (0,0)

In this case;

x =0; y = 0

y = 1\frac{1}{2}x becomes

y = 1\frac{1}{2} * 0

y = 0

<em>The point </em>(0,0)<em>  would be on the graph because the corresponding value of y for </em>x = 0 is y = 0

(e) (2\frac{1}{2},3\frac{3}{4})

In this case:

x = 2\frac{1}{2}; y = 3\frac{3}{4}

y = 1\frac{1}{2}x becomes

y = 1\frac{1}{2} * 2\frac{1}{2}

y = \frac{3}{2} * \frac{5}{2}

y = \frac{15}{4}

y = 3\frac{3}{4}

<em>The point </em>(2\frac{1}{2},3\frac{3}{4}) <em>  would be on the graph because the corresponding value of y for </em>x = 2\frac{1}{2} is y = 3\frac{3}{4}

3 0
3 years ago
given cos θ= √35/6 and angle θ is in Quadrant I, what is the exact value of sin θ in simplest form? Simplify all radicals if nee
joja [24]

Here, I've attached a picture of the triangle that accompanies this explanation.

cot = = =

Now view the triangle.

PS. Angle theta will have a coordinate of (-, +) because it is in quadrant II.

sin of the angle would be opposite/hypotenuse, so sin =

cos of the angle would be adjacent/hypotenuse, so cos =

tan of the angle would be opposite/adjacent, so tan =

3 0
3 years ago
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