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jarptica [38.1K]
1 year ago
15

The writer wants to add a supporting detail toindicate that the story was widely reported. Whichchoice best accomplishes this go

al?A) NO CHANGEB) Other newspapers also ran stories claiming thatthe broadcast had incited mass hysteria.C) In 2013, many newspapers and magazinesfeatured articles about the seventy‑fifthanniversary of the broadcast.D) The Times was then and is now one of theUnited States’ most popular news sources.
Mathematics
1 answer:
mylen [45]1 year ago
4 0

The writer wants to add a supporting detail to indicate that the story was widely reported because Other newspapers also ran stories claiming that the broadcast had incited mass hysteria

The newspaper are periodical publication containing written information about current events and is often typed in black ink with a white or gray background.

Newspapers can cover a wide variety of fields such as politics, business, sports and art, and often include materials such as opinion columns, weather forecasts, reviews of local services, obituaries, birth notices, crosswords, editorial cartoons, comic strips, and advice columns.

Most newspapers are businesses, and they pay their expenses with a mixture of subscription revenue, newsstand sales, and advertising revenue. The journalism organizations that publish newspapers are themselves often metonymically called newspapers.

Newspapers have traditionally been published in print (usually on cheap, low-grade paper called newsprint. However, today most newspapers are also published on websites as online newspapers, and some have even abandoned their print versions entirely.

To know more about newspaper here

brainly.com/question/21528399

#SPJ4

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Complete the statement. 469.1 mg = g
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469.1 mg = .4691 g. Hope I helped. =)
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Charlie has $90 in a savings account. The interest rate is 10%, compounded annually. To the nearest cent, how much interest will
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3 years ago
What is the value of y¹ when y = 5 and x - 10?​
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Answer:

5

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y^1 = 5^1 (y = 5)

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8 0
2 years ago
Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the
Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million)     Number of companies

25 up to 35                                                    4

35 up to 45                                                    19

45 up to 55                                                    27

55 up to 65                                                    16

65 up to 75                                                     9

TOTAL                                                            75

Let's find the probabilities first:

P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}

For 35 up to 45

P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}

For 45 up to 55

P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}

For 55 up to 65

P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}

For 65 up to 75

P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}

Chi-Square Table can be computed as follows:

Expense   No of   Probabilities(P)  Expe                (O-E)^2   \dfrac{(O-E)^2}{E}

             compa                                 cted E (n*p)

             nies (O)  

25-35           4      0.0612    75*0.0612 = 4.59        0.3481       0.0758

35-45           19     0.2218   75*0.2218 = 16.635     5.5932       0.3362

45-55           27     0.3568   75*0.3568 = 26.76     0.0576      0.021

55-65           16      0.2552   75*0.2552 = 19.14      9.8596      0.5151

65-75           9      0.0839     75*0.0839 = 6.2925   7.331         1.1650

                                                                                           \sum \dfrac{(O-E)^2}{E}= 2.0492                                                                                                      

Using the Chi-square formula:

X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square  \ X^2 = 2.0942

Null hypothesis:

H_o: \text{The population of advertising expenses follows a normal distribution}

Alternative hypothesis:  

H_a: \text{The population of advertising expenses does not follows a normal distribution}

Assume that:

\alpha = 0.02

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from X^2 = 11.667

Decision rule: To reject H_o  \  if \  X^2  test statistics is greater than X^2 tabulated.

Conclusion: Since X^2 = 2.0942 is less than critical value 11.667. Then we fail to reject H_o

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3 years ago
I GIVE ANOTHER BRAINLIEST
dlinn [17]

Answer:

Answer Below

Step-by-step explanation:

Triangle #1

To solve this answer we need to multiply then <em>divide by 2</em>

3 x 8=24

24 ÷ 2=12

12

Triangle #2

Now we do the same thing!

3 x 8=24

24 ÷ 2=12

12

Rectangle #1

<em>Now we solve for the rectangle!</em>

6 x 8 = 48

48

Now we add all these together!

12 + 12 + 48 = 72

<em>The answer is D. 72 Square Units</em>

8 0
3 years ago
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