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Gennadij [26K]
2 years ago
14

The vet says Ray's puppy will grow to be at most 28 inches tall. Ray's puppy is currently 1 foot tall. How much more will the pu

ppy grow.
Please write an inequality to answer this question.

Will mark brainliest and is worth 25 points.
Mathematics
1 answer:
Nat2105 [25]2 years ago
4 0

28=12+x

28 represents how tall he will get, 12 represents how tall he is in inches, and x is how much he still has left to grow! Hope it helps!

You might be interested in
you are assembling desserts with a friend together you can make 12 desserts in 5 minutes. how many can you make in 20 minutes?
Sever21 [200]
You can solve this in two ways.

First way:
Let’s find out how many my friend makes in one minute.
12/5=2.4
He makes 2.4 in one minute. Let’s multiply that by 20 to find what he makes in 20 minutes.
2.4•20=48
My friend made 48 desserts.

Second way:
Let’s make a ratio.
12 desserts:5 minutes
X desserts: 20 minutes
Whatever you do to one side, you have to do to the other. Since you are multiplying the minutes by 4, you have to multiply the desserts by 4.
12•4=48

So, my friend made 48 desserts.
Tell me if this helps!!!
3 0
3 years ago
3x+10=4x+10 what is the answer?
ValentinkaMS [17]

Answer:

x is 0.

Step-by-step explanation:

 Subtract both sides by 3x. Then, you will have 10= x+10. Subtract 10 on both sides to isolate x, then you will have x=0. Therefore, this equation on both sides has a solution of 0. Hope this helps!

4 0
2 years ago
Read 2 more answers
Ten times a number is fifty
Rashid [163]

Answer:

5

Step-by-step explanation:

if you multiply 10 and 5, you will get 50

7 0
3 years ago
Read 2 more answers
Find the value of given expression<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B62500%7D%20" id="TexFormula1" title=" \
sashaice [31]

Answer:

250 is the answers for the question

Step-by-step explanation:

please give me brainlest

6 0
3 years ago
Read 2 more answers
Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x' (t) is its velocity, and x'
vodka [1.7K]

Answer:

a) v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

b)  0

c) a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

Step-by-step explanation:

For this case we have defined the following function for the position of the particle:

x(t) = t^3 -6t^2 +9t -5 , 0\leq t\leq 10

Part a

From definition we know that the velocity is the first derivate of the position respect to time and the accelerations is the second derivate of the position respect the time so we have this:

v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

Part b

For this case we need to analyze the velocity function and where is increasing. The velocity function is given by:

v(t) = 3t^2 -12t +9

We can factorize this function as v(t)= 3 (t^2- 4t +3)=3(t-3)(t-1)

So from this we can see that we have two values where the function is equal to 0, t=3 and t=1, since our original interval is 0\leq t\leq 10 we need to analyze the following intervals:

0< t

For this case if we select two values let's say 0.25 and 0.5 we see that

v(0.25) =6.1875, v(0.5)=3.75

And we see that for a=0.5 >0.25=b we have that f(b)>f(a) so then the function is decreasing on this case.  

1

We have a minimum at t=2 since at this value w ehave the vertex of the parabola :

v_x =-\frac{b}{2a}= -\frac{-12}{2*3}= -2

And at t=-2 v(2) = -3 that represent the minimum for this function, we see that if we select two values let's say 1.5 and 1.75

v(1.75) =-2.8125< -2.25= v(1.5) so then the function sis decreasing on the interval 1<t<2

2

We see that the function would be increasing.

3

For this interval we will see that for any two points a,b with a>b we have f(a)>f(b) for example let's say a=3 and b =4

f(a=3) =0 , f(b=4) =9 , f(b)>f(a)

The particle is moving to the right then the velocity is positive so then the answer for this case is: 0

Part c

a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

5 0
3 years ago
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