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Fudgin [204]
3 years ago
12

Can someone help me? Idk how to do the 2nd part. The answer choices for the box are:

Mathematics
2 answers:
s2008m [1.1K]3 years ago
7 0

Answer:

im not sure

Step-by-step explanation:

Grace [21]3 years ago
4 0
I believe the answer is C
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Shannon's little brother is 7 weeks old. She is exactly
Shalnov [3]

Answer:

1147 days

Step-by-step explanation:

3x365= 1095

7x7=49

1095+49+3=1147

4 0
3 years ago
Read 2 more answers
Find the value of y required for
Ulleksa [173]

This is algebra disguised as geometry.  I object.  There are much better ways to combine algebra and geometry.

Anyway, in a parallelogram the diagonals meet at their midpoints, so bisect each other.  So we have two pairs of congruent segments; geometry over.

3x + 1 = x+27

79 - y = 2y + 22

We can ignore the one about x.

79 - 22 = 2y + y

57 = 3y

y = 19

Answer: 19

6 0
3 years ago
Can someone help me with this one?
Nezavi [6.7K]

Answer:

well I can see not see the graph so for this the + whatever is the y intercept which means when the line goes through the y axis and with the X find a point that is at the tip of a square then count up or down and if you count up and over it is positive and down and over it negative if i cann the graph I would love to help you.

6 0
4 years ago
A sports store near Big Bear Lake is having a 20% off sale on all water skis. What will the sale price be for water skis which r
kvasek [131]
248 x 0.8 = $198.40
answer $198.40
8 0
3 years ago
Which statement justifies why ∠ABF measures 130°?
kozerog [31]

Answer:

A. A linear pair is two adjacent, supplementary angles.

Step-by-step explanation:

from the description,

< ABD = 50^{o}, so that;

< ABD + <DBC = 90^{o}

50^{o} + <DBC =  90^{o}

<DBC =  90^{o} -  50^{o}

          = 40^{o}

Thus,

<FBE = < ABD = 50^{o} (vertically opposite angles)

<ABF + <FBE = 180^{o}  (supplementary angles)

<ABF +  50^{o} =  180^{o}

<ABF =  180^{o} - 50^{o}

         = 130^{o}

The statement that justifies why <ABF measures 130^{o} is a linear pair is two adjacent, supplementary angles.

6 0
4 years ago
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