Answer:
12
Step-by-step explanation:
n(AUB) = n((A) + n(B) – n(AnB)
Step 1:
Identify the values for each function of the formula. n(A) = 10, n(B) = 5, n(AnB) = 3
Step 2:
Replace each function with its values
n(AUB) = n(A) + n(B) – n(AnB)
n(AUB) = 10 + 5 – 3
Step 3:
Carry on the simple arithmetic
n(AUB) = 10 + 5 – 3 (follow the BODMAS method)
= 15–3
= 12
Therefore, the n(AUB) is 12
Answer:
Step-by-step explanation:
y= (x -9)^ 1/3
to find the inverse switch x with y and solve for y
x= (y -9)^ 1/3
x³ = y-9
y= x³ +9
Answer:
top left choice
Step-by-step explanation:
A car going at a higher speed than a second car will travel more distance in the same amount of time.
Look at the graph. For example, imagine that each grid line on the x-axis is 1 hour. Look at the 5th grid line to the right of the origin. That would mean 5 hours into the trips.
Now imagine that each grid line on the y-axis is 10 miles.
For the low speed car, at 5 hours, it traveled 40 miles.
For the high speed car, it traveled 70 miles in the same 5 hours.
That makes the x-axis the independent variable representing time, and the y-axis the dependent variable representing position.
Answer: top left choice
Answer:
It's the second option -> y = 1/2x -1
Answer: it takes 5s for each plane to travel their respective distances
Step-by-step explanation:
Let a = speed of plane A
Let b = speed of plane B
b = 55 + a
Time for plane A to fly 4000 miles
= 4000/a
Time for plane B to fly 4275 miles
= 4275/b
Since it takes same amount of time
4000/a = 4275/b
4000b = 4275a-------1
Put b = 55+a in eqn
4000(55+a) = 4275a
220000+4000a = 4275a
275a = 220000
a = 800
b = 55 +800 = 855
Time for plane A to fly 4000 miles
= 4000/800 = 5s
Time for plane B to fly 4275 miles
= 4275/855= 5s