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3 years ago

Please answer the question in the picture!

Mathematics

2 answers:

stira [4]3 years ago

5 0

Hi!

The correct answer is the second one, B. S'(-4, 7), T'(-7, 0), U'(-1, 0)

Explanation:

Because the triangle is translated right 2 units and 3 units down, that means that the x coordinates are translating right 2 units, and the y coordinates are translating down 3 units, which means, to the original x coordinates we will add 2 (because it's going right, in positive way), and we will subtract 3 from the original y coordinates (because it's going down, in negative way), like so:

S(-6, 10) = S'(-6+2, 10-3) = S'(-4, 7)

T(-9, 3) = T'(-9+2, 3-3) = T'(-7, 0)

U(-3, 3) = U'(-3+2, 3-3) = U'(-1, 0)

Hope this helps!

Juli2301 [7.4K]3 years ago

3 0

Eight units I'm pretty sure

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What does 3/216 simplify to

quester [9]

216 divided by 3 is 72 so making the answer

1/72

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3 years ago

Can somebody help me with this question, please? I have no idea how to do this or find the answer. :/ How many ways are there to

san4es73 [151]

Answer:

28 different ways

Step-by-step explanation:

This is a combination question. Combination has to do with selection.

Total number of element in the set = 8

Number divisible by 6 or 8 are {-98, -48, -42, -36, -18, -6}

Total number divisible by 6 or 8 is 6

The number of ways we can choose 6 items from 8 is expressed as;

8C6 = 8!/(8-6)!6!

8C6 = 8!/(2)!6!

8C6 = 8*7*6!/2!6!

8C6 = 8*7/2

8C6 = 56/2

8C6 = 28 ways

Hence there are 28 different ways

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3 years ago

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timurjin [86]

Answer:

f=22 degrees, g=89 degrees

step by step explaination:

When two lines are parallel to one another, and a line is drawn between them, any angle labeled will be equal to the angle on the opposite side of the middle line. This would make f=h, g=d, and even the angle 69 equal to angle e.

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3 years ago

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3 years ago

A piece of wire 11 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria

forsale [732]

Answer:

11 meters

Step-by-step explanation:

First, we can say that the square has a side length of x. The perimeter of the square is 4x, and that is how much wire goes into the square. To maximize the area, we should use all the wire possible, so the remaining wire goes into the triangle, or (11-4x).

The area of the square is x², and the area of an equilateral triangle with side length a is (√3/4)a². Next, 11-4x is equal to the perimeter of the triangle, and since it is equilateral, each side has (11-4x)/3 length. Plugging that in for a, we get the area of the equilateral triangle is

(√3/4)((11-4x)/3)²

= (√3/4)(11/3 - 4x/3)²

= (√3/4)(121/9 - 88x/9 + 16x²/9)

= (16√3/36)x² - (88√3/36)x + (121√3/36)

The total area is then

(16√3/36)x² - (88√3/36)x + (121√3/36) + x²

= (16√3/36 + 1)x² - (88√3/36)x + (121√3/36)

Because the coefficient for x² is positive, the parabola would open up and the derivative of the parabola would be the local minimum. Therefore, to find the maximum area, we need to go to the absolute minimum/maximum points of x (x=0 or x=2.75)

When x=0, each side of the triangle is 11/3 meters long and its area is

(√3/4)a² ≈ 5.82

When x=2.75, each side of the square is 2.75 meters long and its area is

2.75² = 7.5625

Therefore, a maximum is reached when x=2.75, or the wire used for the square is 2.75 * 4 = 11 meters

3 0

3 years ago