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pentagon [3]
3 years ago
8

Please answer the question in the picture!

Mathematics
2 answers:
stira [4]3 years ago
5 0

Hi!

The correct answer is the second one, B. S'(-4, 7), T'(-7, 0), U'(-1, 0)

Explanation:

Because the triangle is translated right 2 units and 3 units down, that means that the x coordinates are translating right 2 units, and the y coordinates are translating down 3 units, which means, to the original x coordinates we will add 2 (because it's going right, in positive way), and we will subtract 3 from the original y coordinates (because it's going down, in negative way), like so:

S(-6, 10) = S'(-6+2, 10-3) = S'(-4, 7)

T(-9, 3) = T'(-9+2, 3-3) = T'(-7, 0)

U(-3, 3) = U'(-3+2, 3-3) = U'(-1, 0)

Hope this helps!

Juli2301 [7.4K]3 years ago
3 0
Eight units I'm pretty sure
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Civil an airport, a factory, and a shopping center are at the vertices of a right triangle formed by three highways. the airport
vekshin1

Answer:

<em>The shortest possible length for the service road is 2.88 miles.</em>

Step-by-step explanation:

According to the below diagram, A, B and C are the positions of airport, shopping center and factory respectively.

Given that,  AB= 3.6 miles, BC= 4.8 miles and AC= 6.0 miles

In right triangle ABC

tan(\angle ACB)=\frac{AB}{BC} \\ \\ tan(\angle ACB)= \frac{3.6}{4.8}=0.75\\ \\ \angle ACB= tan^-^1(0.75)=36.8698.... degree

The shortest possible length for the service road from the shopping center to the highway that connects the airport and factory is BD.

That means, \triangle BCD is also a right triangle in which \angle BDC=90\°, Hypotenuse(BC)= 4.8 miles and BD is the opposite side in respect of \angle DCB or \angle ACB.

Now in right triangle BCD

Sin(\angle ACB)=\frac{BD}{BC}\\ \\ Sin(36.8698...)=\frac{BD}{4.8}\\ \\ BD=4.8*Sin(36.8698...)=2.88

So, the shortest possible length for the service road is 2.88 miles.

4 0
4 years ago
What is the following product? Assume b&gt;0.<br> Square root of b x square root of b
lana [24]

Answer:

√b * ✓b = b (b is the answer to the question)

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3 years ago
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5 0
3 years ago
Read 2 more answers
An example problem in a Statistics textbook asked to find the probability of dying when making a skydiving jump.
MArishka [77]

Answer:

(a) 0.999664

(b) 15052

Step-by-step explanation:

From the given data of recent years,  there were about 3,000,000 skydiving jumps and 21 of them resulted in deaths.

So, the probability of death is \frac{21}{3000000}==0.000007.

Assuming, this probability holds true for each skydiving and does not change in the present time.

So, as every skydiving is an independent event having a fixed probability of dying and there are only two possibilities, the diver will either die or survive, so, all skydiving can be regarded as is Bernoulli's trial.

Denoting the probability of dying in a single jump by q.

q=7\times 10^{-6}=0.000007.

So, the probability of survive, p=1-q

\Rightarrow p=1-7\times 10^{-6}=0.999993.

(a) The total number of jump he made, n=48

Using Bernoulli's equation, the probability of surviving in exactly 48 jumps (r=48) out of 48 jumps (n=48) is

=\binom(n,r)p^rq^{n-r}

=\binom(48,48)(0.999993)^{48}(0.000007)^{48-48}

=(0.999993)^{48}=0.999664 (approx)

So, the probability of survive in 48 skydiving is 0.999664,

(b) The given probability of surviving =90%=0.9

Let, total n skydiving jumps required to meet the surviving probability of 0.9.

So, By using Bernoulli's equation,

0.9=\binom {n }{r} p^rq^{n-r}

Here, r=n.

\Rightarrow 0.9=\binom{n}{n}p^nq^{n-n}

\Rightarrow 0.9=p^n

\Rightarrow 0.9=(0.999993)^n

\Rightarrow \ln(0.9)=n\ln(0.999993) [ taking \log_e both sides]

\Rightarrow n=\frac {\ln(0.9)}{\ln(0.999993)}

\Rightarrow n=15051.45

The number of diving cant be a fractional value, so bound it to the upper integral value.

Hence, the total number of skydiving required to meet the 90% probability of surviving is 15052.

3 0
4 years ago
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andriy [413]
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c. When temperature of water is 15 degree Celsius, then
F = (9 * 15)/5 + 32
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3 years ago
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