PLEASE HELP ASAP!

3r+0.5=18.5 what is r

Crazy boy [7]

18.5-0.5= 18 18/3= 6 So r=6

4 0

3 years ago

Read 2 more answers

In ΔPQR, find the measure of ∡P.

Artyom0805 [142]

Answer:

30.4°

Step-by-step explanation:

< P = arc tan QR/PQ

= arc tan 33.8/57.6

= arc tan 0.5868

= 30.4°

8 0

3 years ago

Tristan can type 57 words every minute. ashley can type 62 words every minute. how many more words can ashley type than tristan

Law Incorporation [45]

Answer:

Ashley can type 475 more words than Tristan in 95 minutes.

Step-by-step explanation:

1. Multiply the amount of words Tristan can type per minute (57) times 95 to get 5,415 typed words in 95 minutes.

2. Multiply the amount of words Ashley can type per minute (62) times 95 to get 5,890 typed words in 95 minutes.

3. Next you subtract Tristan's total amount, 5,415 from Ashley's total amount to get the answer: Ashley can type 475 more words than Tristan in 95 minutes.

Hope this helped

4 0

3 years ago

Please help asap!!!!

pentagon [3]

Answer:

A.) 2

B.) 0

C.) 1/3

D.) 1.25

Step-by-step explanation:

A.) 5(2/3)= 2

B.) 5-5= 0

C.) 2(2/3)-1= 1/3

D.) (1/2)+3/4= 1.25

Hope This Helps! Have A Nice Day!!

3 0

3 years ago

Make 'h' as the subject. Remember to rationalize the denominator while solving.

Sliva [168]

Hello there BeGuiLE !

To solve your question, we must first bring 'h' to one side of the equation. Let's bring all the terms with the variable 'h' to the left side of the equation. So,
$\large{\sf\sqrt{ 3 } h = 1.6+h}$
→ $\large{\sf\sqrt{3}h-h=1.6 }$

Now, let's combine the 2 terms containing the variable 'h'.
$\large{\sf\sqrt{3}h-h=1.6 }$
→ $\large{\sf\left(\sqrt{3}-1\right)h=1.6 }$

Now, we need to leave the variable 'h' alone in the left side of the equation & bring (√3 + 1) to the other side of the equation. This is done in order to make 'h' as the subject of the equation. So, we'll get it as,
$\large{\sf\left(\sqrt{3}-1\right)h=1.6 }$
→ $\large{\sf\:h=\frac{1.6}{\sqrt{3}-1} }$

Now, let's rationalize it. Rationalizing is a process where we move the root from the denominator of a fraction to the numerator for easier calculation. So,
$\large{\sf\:h=\frac{1.6}{\sqrt{3}-1} }$
→ $\large{\sf\:h=\frac{1.6(\sqrt{3}+1)}{(\sqrt{3}-1 )(\sqrt{3}+1}) }$
Now, use the algebraic identity, (a + b)(a - b) = a² - b²
→ $\large{\sf\:h=\frac{1.6(\sqrt{3}+1)}{3-1} }$
→ $\large{\sf\:h=\frac{1.6(\sqrt{3}+1)}{2} }$
→ $\boxed{\large{\sf\:h=0.8(\sqrt{3}+1)}}$

Now, we've made 'h' as the subject of the equation. If you want to solve it more, then,
$\large{\sf\:h=0.8(\sqrt{3}+1)}$
Take √3 as 1.73 (approx. value up to 2 decimal places)
→ $\large{\sf\:h=0.8(1.73+1)}$
→ $\large{\sf\:h=0.8(2.73)}$
→ $\boxed{\boxed{\huge{\bf{\:h=2.184 \: (approx.)}}}}$

I hope this will help you.