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3 years ago

the length of side AB is twice the length of side AC. Write an expression for the perimeter of the triangle

Mathematics

1 answer:

Mamont248 [21]3 years ago

8 0

Answer:

P = 3AC + BC

Step-by-step explanation:

AB = 2AC

P = AB + AC + BC

replace AB

P = 2AC + AC + BC

P = 3AC + BC

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There are 18 books on the summer reading list. In how many different ways can you choose one per week for 8 weeks?

Travka [436]

There are 8 weeks and 18 books. therefore you would multiply these numbers together.
the answer would be 144 different combinations.

not sure about the permutation or combination notation, but I got you on the first part!

5 0

4 years ago

Find the probability that a randomly selected group of five adults will contain all men. Give your answer as a reduced fraction.

Snowcat [4.5K]

Assuming the probability of selecting one man is 1/2 and independent events,

$p = (\frac 1 2)^5 = \frac{1}{32}$

Answer: 1/32

7 0

3 years ago

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Ainat [17]

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4 0

3 years ago

A 9-year-old girl did a science fair experiment in which she tested professional touch therapists to see if they could sense he

Orlov [11]

Answer:

We conclude that the the touch therapists does not use a method equivalent to random guesses.

Yes, the results suggest that touch therapists are effective.

Step-by-step explanation:

We are given that in a 9-year-old girl did a science fair experiment in which she tested professional touch therapists to see if they could sense her energy field.

Among 264264 trials, the touch therapists were correct 105105 times.

Let p = proportion that touch therapists uses a random guess method.

Here, random guess means; p = 50%

So, Null Hypothesis, $H_0$ : p = 50% {means that the touch therapists use a method equivalent to random guesses}

Alternate Hypothesis, $H_A$ : p $\neq$ 50% {means that the touch therapists does not use a method equivalent to random guesses}

The test statistics that would be used here One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of touch therapists were correct = $\frac{105}{264}$ = 0.39

n = sample of trials = 264

So, test statistics = $\frac{\frac{105}{264} -0.50}{\sqrt{\frac{\frac{105}{264}(1-\frac{105}{264})}{264} } }$

= -3.395

The value of z test statistics is -3.395.

Now, at 0.05 significance level the z table gives critical value of -1.96 and 1.96 for two-tailed test. Since our test statistics does not lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the the touch therapists does not use a method equivalent to random guesses.

Yes, the results suggest that touch therapists are effective.

3 0

3 years ago

Please help me someone !!

adelina 88 [10]

Answer:

$6^{\frac{-1}{3}}$