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Otrada [13]
2 years ago
13

If x+3/3 = y+2/2 , then x/3=?

Mathematics
1 answer:
igomit [66]2 years ago
6 0

Answer:

y/3

Step-by-step explanation:

x+1=y+1

x=y+1-1

x=y

Therefore, x/3=y/3

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What is 56/18 in simplest form
Triss [41]

Answer:

The answer in the simplest form would be 28/9 or 3 1/9

Step-by-step explanation:

Very simple you would divide the 56 and the 18 by 2 and you get 28/9.

or you could change it to a improper fraction in that case it would be 3 1/9

6 0
3 years ago
Read 2 more answers
What is the quotient of -18 divided by [-1/6]
Sloan [31]
18?
-18 divided by [-1/6] 
is 18
hopefully that's what you were looking for.?!!
4 0
3 years ago
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I need help with number 11
FinnZ [79.3K]

Answer:

-b/2a is the equation to find the x coordinate of the vertex point and it's y, when x is plugged into the quadratic equation.

Step-by-step explanation:

6 0
2 years ago
B is the midpoint of AC. If Ab= x +5 and BC = 2x-11, find the measure of Ab.
LuckyWell [14K]

__________________________

Measurement of "AC" :

(x + 5) + (2x <span>− 11) ;
________________________

Find the measurement of "AB" [which is: "(x+5)" ]: 
______________________________________________
First, simplify to find the measurement of "AC" :
________________________________________
 </span>(x + 5) + (2x − 11) ;

=  (x + 5) + 1(2x − 11) ;

=   x + 5 + 2x − 11 ;

 → Combine the "like terms" ; 

   x + 2x = 3x ;
   
   5 − 11 = - 6 ;
______________
to get:  3x − 6 ; 
_______________
So,  (x + 5) + (2x − 11) =  3x − 6 ;
_______________________________
Solve for:  "(x + 5)"
_______________________________

We have: 
_______________________________

(x + 5) + (2x − 11) =  3x − 6  ;

Subtract:  "(2x − 11)" ;  from EACH SIDE of the equation ;
                                      to isolate "(x + 5)" on one side of the equation; 
                                      and to solve for "(x + 5)" ;
________________________________________________________
    →  (x + 5) + (2x − 11) − (2x − 11) =  (3x − 6) − (2x − 11) ;
  
         → (x + 5)  = (3x − 6) − (2x − 11) ;
_________________________________________________
  Note:  Simplify:  "(3x − 6) − (2x − 11)" ;

     →  (3x − 6) − (2x − 11)  ;
 
         =  (3x − 6) − 1(2x − 11) ;
 
         =   3x − 6 − 2x + 11 ;
__________________________
   →  Combine the "like terms" :
_____________________________
         +3x − 2x = 1x = x ;
  
          -6 + 11 = 5 ; 
_____________________________
To get:  x + 5 ; 

So we have:
______________________________
 x + 5 = x + 5 ; 
______________________________

So, x = all real numbers.

x = <span>ℝ </span>
4 0
3 years ago
The mean temperature for the first 7 days in January was 6 degrees.The temperature on the 8 days was 10 degrees . What is the me
kolezko [41]

Answer: The mean temperature for the first eight days is 6.5 degrees

Step-by-step explanation: The most important piece of clue has been given which  is the mean (average) for the observed data set, which is 7 days.

Note that the formula for the mean of a data set is derived as;

Mean = ∑x / f

Where ∑x is the summation of all observed data set and f is the number of data observed, that is 7. The formula now becomes;

6 = ∑x / 7

By cross multiplication, we now have,

6 * 7 = ∑x

42 = ∑x

This means the addition of all temperature observed on the first 7 days is 42. The temperature on the eighth day is now given as 10 degrees, this means the summation of all observed data for the first eight days would become 42 + 10 which equals 52. Therefore when calculating the mean for the first eight days, ∑x is now 52. The formula for the first eight days therefore is derived as follows;

Mean = ∑x / 8

Mean = 52 / 8

Mean = 6.5

The calculations therefore show that the mean temperature for the first eight days in January is 6.5 degrees

3 0
3 years ago
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