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Leya [2.2K]
3 years ago
7

What is 5x + 5= -15 A -4 B -9 C -2 D -1

Mathematics
1 answer:
IrinaK [193]3 years ago
6 0
The correct answer is a || move the constant over (5x=-15-5), combine like terms (5x=-20), divide both sides by 5 to get x alone (x=-20/5), solve (x=-4) || please mark brainliest
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x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco
igomit [66]

Answer:

x=-cos(t)+2sin(t)

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

Will have a characteristic equation of the form:

a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0

Where solutions r_1,r_2...,r_n are the roots from which the general solution can be found.

For real roots the solution is given by:

y(t)=c_1e^{r_1t} +c_2e^{r_2t}

For real repeated roots the solution is given by:

y(t)=c_1e^{rt} +c_2te^{rt}

For complex roots the solution is given by:

y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)

Where:

r_1_,_2=\lambda \pm \mu i

Let's find the solution for x''+x=0 using the previous information:

The characteristic equation is:

r^{2} +1=0

So, the roots are given by:

r_1_,_2=0\pm \sqrt{-1} =\pm i

Therefore, the solution is:

x(t)=c_1cos(t)+c_2sin(t)

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of x(t) in order to find the constants c_1 and c_2:

x'(t)=-c_1sin(t)+c_2cos(t)

Evaluating the initial conditions:

x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1

And

x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2

Now we have found the value of the constants, the solution of the second-order IVP is:

x=-cos(t)+2sin(t)

3 0
3 years ago
ANSWER NOW FOR A LOT OF POINTS!
sleet_krkn [62]
Answer: x>2
Explanation:
4x- 2>6
4x>8
x> 2
HOPE IT HELPS!!!:):)
3 0
3 years ago
Please help me with this question
maw [93]
The answer is b with the angles
8 0
3 years ago
An airplane travels 290 km between Austin and Dallas in 1 h 15 min. What is it’s average speed?
aniked [119]

The average speed of the plane between Austin and Dallas is 232 kmph

<u>Solution:</u>

Given that,

Total distance traveled by airplane = 290 km

Time taken for travel between Austin and Dallas = 1 hour 15 minute

Let us convert the time taken to hours

\begin{array}{l}{1 \text { minute }=\frac{1}{60} \text { hours }} \\\\ {15 \text { minutes }=\frac{15}{60}=\frac{1}{4}} \\\\ {\text { 1 hour } 15 \text { minutes }=1 \frac{1}{4} \text { hours }=\frac{1 \times 4+1}{4}=\frac{5}{4} \text { hours }}\end{array}

<em><u>The average speed is given as:</u></em>

\text { Average speed }=\frac{\text { total distance }}{\text { total time taken }}

Plugging in the values, we get,

\text { Average speed }=\frac{290}{\frac{5}{4}}=\frac{290}{5} \times 4=232

Hence the average speed is 232 kmph

6 0
3 years ago
johnny has 27 buttons. he gives away b buttons. choose the expression that shows the number of buttons johnny has left. b,27,bpl
Ksivusya [100]
27-b because you are taking away
6 0
3 years ago
Read 2 more answers
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