Answer:
10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Step-by-step explanation:
In this question, we are tasked with writing the product as a sum.
To do this, we shall be using the sum to product formula below;
cosαsinβ = 1/2[ sin(α + β) - sin(α - β)]
From the question, we can say α= 5x and β= 10x
Plugging these values into the equation, we have
10cos(5x)sin(10x) = (10) × 1/2[sin (5x + 10x) - sin(5x - 10x)]
= 5[sin (15x) - sin (-5x)]
We apply odd identity i.e sin(-x) = -sinx
Thus applying same to sin(-5x)
sin(-5x) = -sin(5x)
Thus;
5[sin (15x) - sin (-5x)] = 5[sin (15x) -(-sin(5x))]
= 5[sin (15x) + sin (5x)]
Hence, 10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Answer:
76
its going by 15's so you add 15
Okay so your equation is going to be : 18= 5k + 3.25p
Answer:
y=x-5
Step-by-step explanation:
Answer: x= 5
Step-by-step explanation:
8x+32=1/5(25x−15)−4x
8x + 32 = <u>25x -15</u> - 4x <u><em>- 25x -15/ 5</em></u>
5
8x + 32 = 5x -3 - 4x
8x + 4x - 5x = -32 - 3
7x =-35
x = 35/7
x= 5
