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Naddika [18.5K]
3 years ago
11

What is the area of the trapezoid shown below?​

Mathematics
2 answers:
Olin [163]3 years ago
7 0

Answer:

78 sqr units

Step-by-step explanation:

Use the Pythagorean Theorem to help find the base opposite the two.

The base of the second parallel line is sqrt(  (15^2) - (12^2)  ) = sqrt(81) = 9

The second base = 9 + 2 = 11

Area = (b1 + b2)*h/2

h = 12

b1 = 2

b2 = 11

h = 12

Area = (11 + 2)*12/2

Area = 13 * 12/2

Area = 78 square units

Murljashka [212]3 years ago
3 0
The answer is seventy eight square units
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7x^2=9+x what are the values of x<br><br>Will give medal and points
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x = \frac{- (-1) \pm  \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}   Cancel out the double negative
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The approximate square root of 253 is <span>15.905973.
</span>x ≈ \left \{ { \frac{1 + 15.905973}{14} } \atop { \frac{1 - 15.905973}{14} }} \right   Add and subtract
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x ≈ \left \{ {{1.2075} \atop {1.0647}} \right.   Round to the nearest hundredth
x ≈ \left \{ {{1.21} \atop {1.06}} \right.

<span>
</span>
7 0
3 years ago
What is the area of the trapezoid shown below?​
Olin [163]

Answer:

78 sqr units

Step-by-step explanation:

Use the Pythagorean Theorem to help find the base opposite the two.

The base of the second parallel line is sqrt(  (15^2) - (12^2)  ) = sqrt(81) = 9

The second base = 9 + 2 = 11

Area = (b1 + b2)*h/2

h = 12

b1 = 2

b2 = 11

h = 12

Area = (11 + 2)*12/2

Area = 13 * 12/2

Area = 78 square units

7 0
3 years ago
Read 2 more answers
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lara [203]

Answer:

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Step-by-step explanation:

I just took the quick check

8 0
2 years ago
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