216 raised to the power 1/3 can also be written as cube root of 216.
Changing the given expression to radical form, we can write:
![(216)^{ \frac{1}{3} } \\ \\ = \sqrt[3]{216}](https://tex.z-dn.net/?f=%28216%29%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%0A%3D%20%5Csqrt%5B3%5D%7B216%7D%20)
216 is the cube of 6 i.e. multiply 6 three times (6 x 6 x 6), you will get 216.
So we can write the above expression as:
![\sqrt[3]{(6)^{3} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%286%29%5E%7B3%7D%20%7D%20)
The cube root and cube cancel out each other, leaving the answer equal to 6.
So, the correct answer is option B
Answer:
Let the number of brownies made by Rachel and Trish be R and T respectively.
R+T= 84 ---------(1)
R= 5(12)= 60
Substitute into (1):
60 + T = 84
T= 84-60
T= 24
Therefore, number of pans of brownies made by Trish
= 24÷12
=2
Alternatively,
Let the number of pans of brownies made by Trish be x.
Total number of pans of brownies= 84/12= 7
Since Rachel contributed 5 pans,
x+5=7
x= 7-5= 2
Thus, Trish made 2 pans of brownies.
<span>Triple 4 and subtract 2 each day
Find the number of days to be able to reach zero
1st day = 3(4) – 2
=> 12 - 2
=> 10
2nd day
=> 10 - 2
=> 8
3rd day
=> 8 – 2
=> 6
4th day
=> 6 – 2
=> 4
5th day
=> 4 – 2
=> 2
6th day
=> 2 – 2
=0
In 6th day, you’ll be able to get the amount of zero by subtracting
3(4) by 2.</span>
1 1/9 because when you divide one by nine it repeats
Answer:
Yes it does
Step-by-step explanation:
The average is shifted to higher side if higher number is present in a data set.
suppose the following set of data
20, 40 , 60, 100
avergae of data= (20+40+60+100)/ 4 = 55
now suppose following set of data
20,40,60,1000
average of data= (20+40+60+1000)/4= 280