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vekshin1
2 years ago
6

A toy American Eskimo dog has a mean weight of 8 pounds with a standard deviation of 1 pound. Assuming the weights of toy Eskimo

dogs are normally distributed, what range of weights would 95% of the dogs have? Approximately 7–9 pounds Approximately 6–10 pounds Approximately 5–11 pounds Approximately 4–12 pounds
Mathematics
1 answer:
Vladimir [108]2 years ago
8 0

Answer:

The correct answer is Approximately 6-10 pounds

Step-by-step explanation:

According to the given statement a toy American Eskimo dog has a mean weight of 8 pounds with a standard deviation of 1 pound

According to normal distribution 95% dogs lie between 2 std deviation on either side of the mean.

Therefore lower bound = 8-2 = 6

Upper bound = 8+2 = 10

Thus the range would be approximately 6–10 pounds ....

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The probability according to the given scenario is:

(a) <em>0.0395</em>

(b) <em>0.95</em>

(c) <em>0.076</em>

The given values are:

  • P(B/A) = 0.79
  • P(A) = 0.05

(a)

The probability that the  b/w has tuberculosis as well as having (+) test will be:

→ P(A \cap B) = P(B/A).P(A)

By substituting the values, we get

→                  = 0.79\times 0.05

→                  = 0.0395

(b)

The probability that a person does not have tuberculosis will be:

→ P(A') = 1-P(A)

→            =1-0.05

→            = 0.95

(c)

The person does not have tuberculosis as well as have a (+) test, the probability will be:

→ P(A' \cap B) = P(A').P(B/A')

→                  = 0.95\times 0.08

→                  = 0.076

Learn more:

brainly.com/question/14816227

8 0
1 year ago
Mr. James has cylindrical beakers that measure 4 inches in diameter and 9 inches high. What is the volume contained within the b
goblinko [34]
So 4 inches diameter result the radius is 4/2 = 2 inches 

area of base = pir^2 = 3,14*2^2 = 3,14*4 = 12,56 inches squared 

volume = area of base *height 

V = 12,56 *9 = 113,04 so rounded 113,05 inches cubed 

hope this will help you 
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