All categories

2 years ago

PLZ HELP ITS DUE IN 28 MINUTES

Mathematics

1 answer:

Ilya [14]2 years ago

4 0

Answer:

I think y and z = 45

You might be interested in

12r r=1/6 Please show your work

Flauer [41]

Answer:

Step-by-step explanation:

If m = 4, z = 9 and r = 1/6

1. 3 + m = 3 + 4 = 7

2. z - m = 9 - 4 = 5

3. 12r = 12 × 1/6 = 2

4. 60r - 4 = 60(1/6) - 4 = 10-4 = 6

5. 4m - 2 = 4(4) - 2 = 16-2 = 14

6 0

2 years ago

Pls help I really need the answer right now

Step2247 [10]

Use photo-math or Gauth-math application can help u this

5 0

2 years ago

I need help with this question asap

guajiro [1.7K]

((2t+10) / 2) + ((3t-15) / 2) + (3s) = 180
((2t+10) / 2) + ((3t-15) / 2) + (4r) = 180
((2t+10) / 2) + ((3t-15) / 2) + (3s) = ((2t+10) / 2) + ((3t-15) / 2) + (4r)
(2t+10) = (3t-15) t=25
2*25+10= 60 , 3*25-15=60
60+60= 120 , This rectangle has a total of 360 degrees
360 - 120 = 240
240/2 =120
120/ 4 = 30 , 120/3 = 40
r=30 s=40

6 0

2 years ago

Use l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove

steposvetlana [31]

Answer:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}$

Step-by-step explanation:

The limit is:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}$

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

$\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}$

by replacing, and applying repeatedly you obtain:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}$

hence, the limit of the function is -1/14

8 0

3 years ago

PLEASE HELP! write an expression ( simplified ) for the perimeter of the given figure

liraira [26]

Answer:

Step-by-step explanation:

2(3x-1)+2(6)

6x-2+12

6x+10

8 0

3 years ago

Read 2 more answers