Find the perimeter of the given triangle
1 answer:
ABC is similar to PQR
that means AC/PR is a constant = 12/ 6 = 2
AC= 2 PR
AB= 2PQ
BC= 2QR
Perimeter of ABC= AB+BC+ CA=
2PQ + 2 QR + 2PR= 2( PQ+ QR+ PR)
= 2( perimeter of triangle PQR )
Perimeter of ABC= 2( perimeter of PQR) = 2* 36 = 72
Answer : 72.
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