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4 years ago

Find the perimeter of the given triangle

Mathematics

1 answer:

faltersainse [42]4 years ago

8 0

ABC is similar to PQR

that means AC/PR is a constant = 12/ 6 = 2

AC= 2 PR

AB= 2PQ

BC= 2QR

Perimeter of ABC= AB+BC+ CA=

2PQ + 2 QR + 2PR= 2( PQ+ QR+ PR)

= 2( perimeter of triangle PQR )

Perimeter of ABC= 2( perimeter of PQR) = 2* 36 = 72

Answer : 72.

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3 years ago

How long will it take dara to read 540 pages

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3 years ago

For X a binomial random variable with n=5 and p=1/4, answer the following

mash [69]

Recall that for $X\sim\mathrm{Bin}(n,p)$ , i.e. a random variable $X$ following a binomial distribution over $n$ trials and with probability parameter $p$ ,

$\mathbb P(X=x)=f_X(x)=\begin{cases}\dbinom nx p^x(1-p)^{n-x}&\text{for }x\in\{0,1,\ldots,n\}\\\\0&\text{otherwise}\end{cases}$

So you have

$\mathbb P(X=2)=\dbinom52\left(\dfrac14\right)^2\left(1-\dfrac34\right)^{5-2}=\dfrac{135}{512}\approx0.26$

$\mathbb P(2\le X\le4)=\displaystyle\sum_{x=2}^4\mathbb P(X=x)$
$=\dbinom52\left(\dfrac14\right)^2\left(1-\dfrac14\right)^{5-2}+\dbinom52\left(\dfrac14\right)^3\left(1-\dfrac14\right)^{5-3}+\dbinom52\left(\dfrac14\right)^4\left(1-\dfrac14\right)^{5-4}$
$=\dfrac{375}{1024}\approx0.37$

The expected value of $X\sim\mathrm{Bin}(n,p)$ is simply $np$ , while the standard deviation is $\sqrt{np(1-p)}$ . In this case, they are $\dfrac54=1.25$ and $\sqrt{\dfrac{15}{16}}\approx0.97$ , respectively.

7 0

3 years ago

Please help with this I still do not know what I am doing

amm1812

Answer:

See Below

Step-by-step explanation:

150 = p + 78 ------ you want to get the p to one side and the other number the the other side of the =

(78 - 150) = p (78 - 78) ---- what ever you do to one side you do to the other

72 = p

s - 51 = 12 (same thing as above)

s (-51 + 51) = 12 + 51

s = 63

65 = blank + 7 ( you can put a letter like x or y because they number is not determined yet)

65 = x + 7 (same as above)

( 7 - 65 ) = x ( 7 - 7 )

58 = x

6 0

3 years ago