All categories

2 years ago

Given that AB parallels QR, AB bisects AE, QR bisects QT

Mathematics

1 answer:

enyata [817]2 years ago

5 0

Answer:

1. Dilate ΔABE by a factor of 2/5 to make ΔA'B'E'

2. Translate A' to Q

Step-by-step explanation:

We notice the triangles have the same orientation, so no reflection or rotation is involved. The desired mapping can be accomplished by dilation and translation:

1. Dilate ΔABE by a factor of 2/5 to make ΔA'B'E'

2. Translate A' to Q

The result will be that ΔA"B"E" will lie on top of ΔQRT, as required.

You might be interested in

An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed

masya89 [10]

Answer:

$P(X\leq 1) = 0.331$

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

$P(X = x) = \frac{y^xe^{-y}}{x!}$

Where y represents λ (average)

y = 2.3

Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment

Using probability notations;

$P(X\leq 1) = P(X=0) + P(X =1)$

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

$P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}$

$P(X = 0) = \frac{1 * e^{-2.3}}{1}$

$P(X = 0) = e^{-2.3}$

$P(X = 0) = 0.10025884372$

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

$P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}$

$P(X = 1) = \frac{2.3 * e^{-2.3}}{1}$

$P(X = 1) =2.3 * e^{-2.3}$

$P(X = 1) = 2.3 * 0.10025884372$

$P(X = 1) = 0.23059534055$

$P(X\leq 1) = P(X=0) + P(X =1)$

$P(X\leq 1) = 0.10025884372 + 0.23059534055$

$P(X\leq 1) = 0.33085418427$

$P(X\leq 1) = 0.331$

Hence, the required probability is 0.331

6 0

2 years ago

A spyware is trying to break into a system by guessing its password. It does not give up until it tries 1 million different pass

Anettt [7]

Answer:

$Probability = 0.006033$

Step-by-step explanation:

Given

$Tries = 1000000$

Required

Determine the probability of 6 different lower case letters (Question continuation)

There are 26 lower case letters.

The first can be any of letters 26

The second can be any of letters 26 - 1

The third can be any of letters 26 - 2

The fourth can be any of letters 26 - 3

The fifth can be any of letters 26 - 4

The sixth can be any of letters 26 - 5

Number of selection is:

$Selection = 26 * (26 - 1) * (26 - 2) * (26 - 3) * (26 - 4) * (26 - 5)$

$Selection = 26 * 25 * 24 * 23 * 22 * 21$

$Selection = 165765600$

The probability is:

$Probability = \frac{Tries}{Selection}$

$Probability = \frac{1000000}{165765600}$

$Probability = 0.00603261472$

$Probability = 0.006033$ --- approximated

6 0

2 years ago

Evaluate the expression for the given value of the variable.

MatroZZZ [7]

Answer:

Step-by-step explanation:

24/t + t^2

Let t=3

24/3 + 3^2

8 + 9

5 0

2 years ago

Read 2 more answers

Can i pleaseee get help:(

AfilCa [17]

Answer:

Step-by-step explanation:

P=5/25=1/5=0.20

8 0

2 years ago

Read 2 more answers

Battery packs in electric go-carts need to last a fairly long time. The run-times (time until it needs to be recharged) of the b

pav-90 [236]

Answer:

The minimum level for which the battery pack will be classified as highly sought-after class is 2.42 hours

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 2, \sigma = 0.33$