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3 years ago

Given that AB parallels QR, AB bisects AE, QR bisects QT

Mathematics

1 answer:

enyata [817]3 years ago

5 0

Answer:

1. Dilate ΔABE by a factor of 2/5 to make ΔA'B'E'

2. Translate A' to Q

Step-by-step explanation:

We notice the triangles have the same orientation, so no reflection or rotation is involved. The desired mapping can be accomplished by dilation and translation:

1. Dilate ΔABE by a factor of 2/5 to make ΔA'B'E'

2. Translate A' to Q

The result will be that ΔA"B"E" will lie on top of ΔQRT, as required.

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If you are dealt five cards from a shuffled deck of 52 cards find the probability of getting three queens and two kings

dexar [7]

The probability of getting three queens and two kings is $\frac{1}{1082900}$

Solution:

Given that , you are dealt five cards from a shuffled deck of 52 cards

We have to find the probability of getting three queens and two kings

Now, we know that, in a deck of 52 cards, we will have 4 queens and 4 kings.

$\text { probability of an event }=\frac{\text { favarable possibilities }}{\text { number of possibilities }}$

Probability of first queen:

$\text { Probability for } 1^{\text {st }} \text { queen }=\frac{4}{52}=\frac{1}{13}$

Probability of second queen:

$\text { Plobability for } 2^{\text {nd }} \text { queen }=\frac{3}{51}=\frac{1}{17}$

Here we used 3 for favourable outcome, since we already drew 1 queen out of 4

And now number of outcomes = 52 – 1 = 51

Probability of third queen:

Similarly here favorable outcome = 2, since we already drew 2 queen out of 4

And now number of outcomes = 51 – 1 = 50

$\text { Probability of } 3^{\text {rd }} \text { queen }=\frac{2}{50}=\frac{1}{25}$

Probability for first king:

Here kings are 4, but overall cards are 49 as 3 queens are drawn

$\text { probability for } 1^{\text {st }} \text { king }=\frac{4}{49}$

Probability for second king:

Here, kings are 3 and overall cards are 48 as 3 queens and 1 king are drawn

$\text { probability of } 2^{\text {nd }} \text { king }=\frac{3}{48}=\frac{1}{16}$

And, finally the overall probability to get 3 queens and 2 kings is:

$=\frac{1}{13} \times \frac{1}{17} \times \frac{1}{25} \times \frac{4}{49} \times \frac{1}{16}=\frac{4}{4331600}=\frac{1}{1082900}$

Hence, the probability is $\frac{1}{1082900}$

7 0

3 years ago

Internal memoriam menino

polet [3.4K]

Answer:

L = 90 yards
W = 60 yards

Step-by-step explanation:

The formula for the perimeter of a rectangle is ...

P = 2(L+W)

If the length is 30 yards more than the width, we can use L = W+30 and substitute known values into the above formula:

300 = 2((W+30) +W)

150 = 2W +30 . . . . . divide by 2 and collect terms

120 = 2W . . . . . . . . . subtract 30

60 = W . . . . . . . . . . . divide by 2

60+30 = L = 90

The length is 90 yards; the width is 60 yards.

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4 years ago

于 8) (11+ 3) + (14 +84) = (11+3) + 14+8\4=

bulgar [2K]

Answer:

what year are you?

Step-by-step explanation:

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7 0

3 years ago

What is -7 / 4 * 11 / 7

stich3 [128]

Answer:

-2.75

Step-by-step explanation:

You divide first then multiply the two answers you get together.

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3 years ago

Help please someone!!? ):

gregori [183]

Yourrr wellllcomeeeee

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3 years ago