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2 years ago

Given that AB parallels QR, AB bisects AE, QR bisects QT

Mathematics

1 answer:

enyata [817]2 years ago

5 0

Answer:

1. Dilate ΔABE by a factor of 2/5 to make ΔA'B'E'

2. Translate A' to Q

Step-by-step explanation:

We notice the triangles have the same orientation, so no reflection or rotation is involved. The desired mapping can be accomplished by dilation and translation:

1. Dilate ΔABE by a factor of 2/5 to make ΔA'B'E'

2. Translate A' to Q

The result will be that ΔA"B"E" will lie on top of ΔQRT, as required.

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Write a two column proof

Annette [7]

$4y=2x-10$ and $y=6$

use the second expression to calculate the left-hand side of the first equation:

$4\cdot 6 = 2x -10\\24 = 2x -10$

Add 10 to both sides if this equation to get

$34 = 2x$

and divide both sides by 2

$17 = x$

this proves that x = 17, give the two initial equations

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3 years ago

Bought three books: 150, if one book cost 50% more than the other two combined what was the price of the more expensive book

EleoNora [17]

Two cheaper books = x
more expensive = 1.5x
so, 2.5x=150
150/2.5=x=60
therefore the more expensive book = 90

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3 years ago

If you toss three coins, what are the odds in favor of getting exactly two tails and one head?

jekas [21]

Answer:

I think the answer is 3:5

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3 years ago

When 258 college students are randomly selected and surveyed, it is found that 106 own a car. Find a 99% confidence interval for

juin [17]

Answer: 0.332 < p < 0.490

Step-by-step explanation:

We know that the confidence interval for population proportion is given by :-

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where n= sample size

$\hat{p}$ = sample proportion

z* = critical z-value.

As per given , we have

n= 258

Sample proportion of college students who own a car = $\hat{p}=\dfrac{106}{258}\approx0.411$

Critical z-value for 99% confidence interval is 2.576. (By z-table)

Therefore , the 99% confidence interval for the true proportion(p) of all college students who own a car will be : $0.411\pm (2.576)\sqrt{\dfrac{0.411(1-0.411)}{258}}\\\\=0.411\pm (2.576)\sqrt{0.00093829}\\\\= 0.411\pm (2.576)(0.0306315197142)\\\\=0.411\pm 0.0789=(0.411-0.0789,\ 0.411+0.0789)\\\\=(0.3321,\ 0.4899)\approx(0.332,\ 0.490)$

Hence, a 99% confidence interval for the true proportion of all college students who own a car : 0.332 < p < 0.490

3 0

3 years ago

Brainliest and points! HELP ABOUT MEAN EASY!!

Luden [163]

To work it out:
(20200 + 14500 + 18800 + 9300 + 2200) divide by the number of regions, in this case 5.
The answer is 13000 which is A

Basically the mean is adding all the numbers divided by the amount of numbers you added. So in this case adding the data of the 5 regions divided by 5.

Hope to have helped :)

8 0

3 years ago