Given that AB parallels QR, AB bisects AE, QR bisects QT
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Let's first find the slope. This is (y_2 - y_1)/(x_2 - x_1), where (x_1, y_1) and (x_2, y_2) are points.
For this problem, our slope is (0 - 2)/(3 - 0) = -2/3.
We can now use the point-slope formula to find the equation of our line:
(y - y_1) = m(x - x_1)
(y - 2) = -2/3(x - 0)
y - 2 = (-2/3)x
y = (-2/3)x + 2
The equation of our line is
.
For this problem, our slope is (0 - 2)/(3 - 0) = -2/3.
We can now use the point-slope formula to find the equation of our line:
(y - y_1) = m(x - x_1)
(y - 2) = -2/3(x - 0)
y - 2 = (-2/3)x
y = (-2/3)x + 2
The equation of our line is