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olga nikolaevna [1]
2 years ago
7

1 a-2a-{3a-(4a-5)} i need help plz and on this one to 13(5-t)-(5-t)-12(5-t)

Mathematics
1 answer:
Vladimir [108]2 years ago
5 0
13(5-t)-(5-t)-12(5-t)
=65-13t-5-t-60+12t
=-13t-t+12t+65-5-60
=-2t

a-2a-{3a-(4a-5)}
=a-2a-3a-4a-5
=-8a-5
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miss Akunina [59]

Answer:

Probability that she selects a blue bead

= 3/9

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Step-by-step explanation:

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How can a rational number and irrational number when multiplied together make a irrational number ?
pochemuha

Answer:

"The product of a rational number and an irrational number is SOMETIMES irrational." If you multiply any irrational number by the rational number zero, the result will be zero, which is rational. Any other situation, however, of a rational times an irrational will be irrational

A better statement would be:

"The product of a non-zero rational number and an irrational number is irrational

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2 years ago
Find the components of the vertical force Bold Upper Fequalsleft angle 0 comma negative 8 right anglein the directions parallel
nydimaria [60]

Answer with Step-by-step explanation:

We are given that

F=<0,-8>=0i-8j=-8j

\theta=\frac{\pi}{3}

The component of force is divided into two direction

1.Along the plane

2.Perpendicular to the plane

1.The vector parallel to the plane will be=r=cos\frac{\pi}{3}i-sin\frac{\pi}{3}j=\frac{1}{2}i-\frac{\sqrt 3}{2}j

By using cos\frac{\pi}{3}=\frac{1}{2},sin\frac{\pi}{3}=\frac{\sqrt 3}{2}

Force along the plane will be=\mid F_x\mid=F\cdot r

Force along the plane will be =\mid F_x\mid=F\cdot (\frac{1}{2}i-\frac{\sqrt 3}{2}j)=-8j\cdot(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=8\times \frac{\sqrt 3}{2}=4\sqrt 3N

By using i\cdot i=j\cdoty j=k\cdot k=1,i\cdot j=j\cdot k=k\cdot i=j\cdot i=k\cdot j=i\cdot k=0

Therefore, force along the plane=\mid F_x\mid(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)

2.The vector perpendicular to the plane=r=-sin\frac{\pi}{3}-cos\frac{\pi}{3}=-\frac{\sqrt 3}{2}i-\frac{1}{2}j

The force perpendicular to the plane=\mid F_y\mid=F\cdot r=-8j(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

The force perpendicular to the plane=4N

Therefore, F_y=4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

Sum of two component of force=F_x+F_y=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)+4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

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3 years ago
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miskamm [114]

Answer:

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Let first test be TEST A: which is 20 of total and secures 62

Let second test be TEST B: which is 20 of the total marks and has secured 83.

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