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m_a_m_a [10]
3 years ago
11

What do two equivalent expressions ALWAYS have in common?

Mathematics
1 answer:
Nadya [2.5K]3 years ago
6 0
It’s c the same constant. Have a nice day!
You might be interested in
For the data set below which of the following measures is greatest? 3,3,4,5,6,8,16,20
MAXImum [283]

Answer:

range

Step-by-step explanation:

Mean- add all the numbers up and divide by how many numbers you added

65/8 =8.125

Range- Find the largest number and subtract the smallest number from it

20-3 =17

Median- put the numbers in order from least to greatest and find the number/s in the middle

3,3,4,5,6,8,16,20- since there are an even amount of numbers add the two in the middle and divide by 2  

5+6=11   11/2 = 5.5

Mode- the number that repeats the most

3 repeats the most

8 0
3 years ago
Answer Asap!
Dmitry_Shevchenko [17]

Answer:

a) RTP

b) MN

c) x=7

Step-by-step explanation:

hope this helps

5 0
3 years ago
Express your answer in scientific notation.
melomori [17]
It’s 1.77 times 10to the 6th
3 0
3 years ago
3. What value of y makes the following equation true? *
Anna71 [15]

Answer:

hahahaha is not easy ??????????????????

5 0
3 years ago
There are 50 deer in a particular forest. The population is increasing at a rate of 15% per year. Which exponential growth funct
NemiM [27]

Answer:

The expression that represents the number of deer in the forest is

y(x) = 50*(1.013)^x

Step-by-step explanation:

Assuming that the number of deer is "y" and the number of months is "x", then after the first month the number of deer is:

y(1) = 50*(1+ 0.15/12) = 50*(1.0125) = 50.625

y(2) = y(1)*(1.0125) = y(0)*(1.0125)² =51.258

y(3) = y(2)*(1.0125) = y(0)*(1.0125)³ = 51.898

This keeps going as the time goes on, so we can model this growth with the equation:

y(x) = 50*(1 - 0.15/12)^(x)

y(x) = 50*(1.013)^x

8 0
4 years ago
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