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sweet-ann [11.9K]
4 years ago
14

Which of the following relations is NOT a function?

Mathematics
1 answer:
Anni [7]4 years ago
6 0

Answer:

C. (2,4), (-3,2)(2,1)(-7,2) is not a function.

Step-by-step explanation:

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Evaluate f(t)=-2t^2+ 1 for f(-3). please help
VARVARA [1.3K]

Answer:

-17

Step-by-step explanation:

f(t)=-2t^2+ 1

f(-3)=-2*-3^2+1

f(-3)=-2*9+1

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3 years ago
Need help pleaseI was bad at math in school so lwant to learn
aleksklad [387]

The probability of an event is expressed as

Pr(\text{event) =}\frac{Total\text{ number of favourable/desired outcome}}{Tota\text{l number of possible outcome}}

Given:

\begin{gathered} \text{Red}\Rightarrow2 \\ \text{Green}\Rightarrow3 \\ \text{Blue}\Rightarrow2 \\ \Rightarrow Total\text{ number of balls = 2+3+2=7 balls} \end{gathered}

The probability of drwing two blue balls one after the other is expressed as

Pr(\text{blue)}\times Pr(blue)

For the first draw:

\begin{gathered} Pr(\text{blue) = }\frac{number\text{ of blue balls}}{total\text{ number of balls}} \\ =\frac{2}{7} \end{gathered}

For the second draw, we have only 1 blue ball left out of a total of 6 balls (since a blue ball with drawn earlier).

Thus,

\begin{gathered} Pr(\text{blue)}=\frac{number\text{ of blue balls left}}{total\text{ number of balls left}} \\ =\frac{1}{6} \end{gathered}

The probability of drawing two blue balls one after the other is evaluted as

\begin{gathered} \frac{1}{6}\times\frac{2}{7} \\ =\frac{1}{21} \end{gathered}

The probablity that none of the balls drawn is blue is evaluted as

\begin{gathered} 1-\frac{1}{21} \\ =\frac{20}{21} \end{gathered}

Hence, the probablity that none of the balls drawn is blue is evaluted as

\frac{20}{21}

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1 year ago
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Answer:

<QPS and <TSU

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3 years ago
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