Answer:
The relative change from 6546 and 4392 is 49.04
Step-by-step explanation:
Answer: -√1/✓41
Step-by-step explanation:
Let y be the irrational number that will be multiplied by -√41 to get the product that equals 1.
y × (-√41) = 1
We then solve for y, by dividing through with -√41. This will be:
[y × (-√41)]/-√41 = 1/-√41
y = -1/√41
y = -√1/✓41
The irrational number is negative root one over root forty one.
Answer: True
Solution:
Rearrange the equation to the LHS:
[x^2 + 8x + 16] · [x^2 – 8x + 16] - (x^2 – 16)^2 = 0
Factoring x^2+8x+16
x^2 - 4x - 4x - 16
= (x-4) • (x-4)
= = (x+4)2
So now we have an equation
(x + 4)^2 • (x - 4)^2 - (x^2 - 16)^2 = 0
Step 2: Evaluate the following:
(x+4)2 = x^2+8x+16
(x-4)2 = x^2-8x+16
(x^2-16)2 = x^4-32x^2+256
(x^2+8x+16) (x^2-8x+16 ) - (x^4-32x^2+256 )
0 = 0
Hence True
Answer:
85
Step-by-step explanation:
The line of the right measures 65 degrees (I think), an the line on the left measures 150 degrees. So, 150 - 65 = 85 degrees.
Answer:
Density is defined as:
Density = mass/volume.
We know that:
For liquid A:
Density = 70kg/m^3
Mass = 1400kg
Then the volume is:
Volume = mass/density = (1400kg)/(70kg/m^3) = 20 m^3
For liquid B:
Density = 280 kg/m^3
Volume = 30m^3
We can find the mass of liquid B as:
mass = density*volume = (280kg/m^3)*(30m^3) = 8400 kg
We know that liquid C is a mixture of liquid A and B.
Then the mass of liquid C will be equal to the sum of the masses of liquid A and B, then:
Mass of liquid C = 1400kg + 8400kg = 9800kg
The same happens for the volume, then:
Volume of liquid C = 30m^3 + 20m^3 = 50m^3
Then the density of liquid C is:
Density of liquid C = (9800kg)/(50m^3) = 196 kg/m^3
