There are total of 5 digits, of which we arrange 3 of them.
Therefore using permutations we can find total possible 3-number combinations.
5P3 = 5*4*3 = 60
To be greater than 600 means first digit must be 6. (1 possibility)
A number is even only if last digit is even, 2 or 4. (2 possibilities)
The 2nd digit then can only be 3,5, (2 or 4). (3 possibilities)
The total possible even 3-digit numbers greater than 600 is product of each digit's possibilities.
---> 1*3*2 = 6
Therefore probability is 6/60 = 1/10.
It would be: -7/12 + 7/10 = -35+42 /60 = 7/60
So, your final answer is 7/60
Hope this helps!
Answer:
(A) 2^{5} * 5 * 7
Step-by-step explanation:
Your question formatting made it very complicated to understand the possible answers. Please use some notation or the equation editor next time.
So, the exponential form a way to write a number using multiplications and powers.
Let's examine the various options (if I read them correctly)
(A) 2^{5} * 5 * 7 - YES!
2^{5} is 32, so 32 * 5 * 7 = 160 * 7 = 1120
(B) 5² · 8 - NO
= 25 * 8 = 200
(C) 2² * 5³ * 7 - NO
= 4 * 125 * 7 =500 * 7 = 3500
(D) 2 · 5 · 7 - NO
= 10 * 7 = 70
Answer:
Step-by-step explanation:
Look at where -2 is on the x-axis (the left side of the horizontal line), and go another half a box in, that is -2.5. But then go down one box from there, and plot the point. that is (-2.5,-1).
Next go half a box to the right and two boxes up, and plot your point there. that is (.5,2).
