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3 years ago

1. There are 4 quarters in 1 dollar.

Mathematics

2 answers:

Mashutka [201]3 years ago

5 0

There are 50 cents in 1/2 of a dollar.

PolarNik [594]3 years ago

3 0

25 cents you dumb stupid child

You might be interested in

Explanation please will give brainliest.

Sonja [21]

Answer:

$AC = 28$

Step-by-step explanation:

Given

$AB = 16$

$BC = 12$

Required

Determine AC

Since A, B and C are collinear, then:

$AC = AB + BC$

So, we have:

$AC = 16 + 12$

$AC = 28$

5 0

3 years ago

Which of these is NOT an integer

Tema [17]

Hi there!

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I believe your answer is:

Option A

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Here’s why:

⸻⸻⸻⸻

$\boxed{\text{Option A:}}\\\\3^{-5}\\\\\rightarrow \frac{1}{3^5}\\\\\rightarrow \frac{1}{243}\\\\\ \text{This is \textbf{NOT} an integer.}}$

⸻⸻⸻⸻

$\boxed{\text{Option B:}}\\\\-3^5\\\\\rightarrow -3 * -3 * -3 * -3 * -3 \\\\\rightarrow \boxed{-243}\\\\\\\text{This \textbf{IS} an integer.}$

⸻⸻⸻⸻

$\boxed{\text{Option C:}}\\\\\frac{1}{3}^{-5} \\\\\rightarrow \frac{1}{(\frac{1}{3})^5}\\\\\rightarrow \frac{1}{\frac{1}{243} }\\\\\rightarrow \boxed{243}\\\\\\\text{This \textbf{IS} an integer.}$

⸻⸻⸻⸻

$\text{Option \textbf{A} does not simplify into an integer.}$

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»»————-　★　————-««

Hope this helps you. I apologize if it’s incorrect.

7 0

2 years ago

What are the roots of the polynomial equation x^3-5x+5=2x^2-5? Use a graphing calculator and a system of equations. Round nonint

leonid [27]

The right answer is c. –2.24, 2, 2.24

This question needs to be solved in two ways. First, using a graphing calculator. Next, using a system of equations.

1. Using a graphing calculator.

We have the following polynomial equation:

$x^3-5x+5=2x^2-5$

By ordering this equation we have:

$x^3-2x^2-5x+10=0$

So, we can say that this equation comes from a function given by:

$f(x)=x^3-2x^2-5x+10$

Thus, by plotting this function, we have that the graph of this function is indicated in Figure 1. By zooming, we can see, in Figure 2, that the roots of the polynomial equation are the x-intercepts of $f(x)$ which are:

$x_{1}=-2.236 \\ \\ x_{2}=2 \\ \\ x_{3}=2.236$

Finally, rounding noninteger roots to the nearest hundredth we have:

$\boxed{Root_{1}=-2.24} \\ \\ \boxed{Root_{2}=2} \\ \\ \boxed{Root_{3}=2.24}$

2. Using a system of equations.

The ordered equation is:

$x^3-2x^2-5x+10=0$

By arranging to factor out we have:

$x^3-5x-2x^2+10=0$

Then, by factoring:

$x(x^2-5)-2(x^2-5)=0$

Term $(x^2-5)$ is a common factor, thus:

$(x-2)(x^2-5)=0 \\ \\ (x-2)(x-\sqrt{5})(x+\sqrt{5})=0 \\ \\ Finally: \\ \\ \boxed{Root_{1}=-\sqrt{5}=-2.24} \\ \\ \boxed{Root_{2}=2} \\ \\ \boxed{Root_{3}=\sqrt{5}=2.24}$

6 0

3 years ago

Read 2 more answers

WHOEVER ANSWERS THE FASTEST WINS BRAINIEST ANSWER AND GETS 98 POINTS FOR THIS QUESTION!!!!!! WHO CAN DO IT?

olga nikolaevna [1]

coordinates of b'a'c are

A:(-5,6)

B:(-5,10)

C:(-3,8)

ANswers of ' are

A'(-6,5)

B'(-10,5)

C'(-8,3)

hope this helped

3 0

2 years ago

Read 2 more answers

The measure of two vertical angles are 6x - 22 and 4x + 2. Find x.

maks197457 [2]

Vertical angles are congruent...they are equal....so set them equal to each other and solve for x

6x - 22 = 4x + 2
6x - 4x = 2 + 22
2x = 24
x = 24/2
x = 12 <==

6 0

3 years ago