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aniked [119]
3 years ago
8

If Anthony has twice as nickels as one and one has 15 more nickels than Maria what is the value in dollars of Anthony's Nickels

if Maria has six Nickels
Explain?
Mathematics
1 answer:
worty [1.4K]3 years ago
4 0

Answer:

Anthony has $2.10

Step-by-step explanation:

If Maria has 6 nickels and one has 15 more nickels than Maria, one has a total of 21 nickels. Since Anthony has twice the amount of nickels as One, you would multiply 21 by 2 to get a total of 42. It takes 20 nickels to make a dollar. If you divide 42 by 20 you get 2.1, which is equivaldnt to $2.10

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natta225 [31]

Answer:

a) 99% of the sample means will fall between 0.933 and 0.941.

b) By the Central Limit Theorem, approximately normal, with mean 0.937 and standard deviation 0.0015.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

(a) If the true mean is 0.9370 with a standard deviation of 0.0090 within what interval will 99% of the sample means fail?

Samples of 34 means that n = 34

We have that \mu = 0.937, \sigma = 0.009

By the Central Limit Theorem, s = \frac{0.009}{\sqrt{34}} = 0.0015

Within what interval will 99% of the sample means fail?

Between the (100-99)/2 = 0.5th percentile and the (100+99)/2 = 99.5th percentile.

0.5th percentile:

X when Z has a pvalue of 0.005. So X when Z = -2.575.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

-2.575 = \frac{X - 0.937}{0.0015}

X - 0.937 = -2.575*0.0015

X = 0.933

99.5th percentile:

X when Z has a pvalue of 0.995. So X when Z = 2.575.

Z = \frac{X - \mu}{s}

2.575 = \frac{X - 0.937}{0.0015}

X - 0.937 = 2.575*0.0015

X = 0.941

99% of the sample means will fall between 0.933 and 0.941.

(b) If the true mean 0.9370 with a standard deviation of 0.0090, what is the sampling distribution of ¯X?

By the Central Limit Theorem, approximately normal, with mean 0.937 and standard deviation 0.0015.

6 0
3 years ago
What is the value of x
Zolol [24]

Answer:

765854sdfgh

Step-by-step explanation:

6 0
3 years ago
Consider f and c below. f(x, y, z) = (y2z + 2xz2)i + 2xyzj + (xy2 + 2x2z)k,
qaws [65]
\dfrac{\partial f}{\partial x}=y^2z+2xz^2
f(x,y,z)=xy^2z+x^2z^2+g(y,z)

\dfrac{\partial f}{\partial y}=2xyz+\dfrac{\partial g}{\partial y}=2xyz
\dfrac{\partial g}{\partial y}=0\implies g(y,z)=h(z)

\dfrac{\partial f}{\partial z}=xy^2+2x^2z+\dfrac{\mathrm dh}{\mathrm dz}=xy^2+2x^2z
\dfrac{\mathrm dh}{\mathrm dz}=0\implies h(z)=0

\implies f(x,y,z)=xy^2z+x^2z^2+C
8 0
3 years ago
PLEASEEEEEEE HELP ME!!!
igor_vitrenko [27]

Answer:

125π km³

Step-by-step explanation:

We are to find the Volume of a cylinder

From the question:

Height of the cylinder = 5km

Radius of the cylinder = 5 km

The volume of a cylinder =

πr² h

Hence:

π × 5² × 5

= 125π km³

The volume of the cylinder = 125π km³

Option d is the correct option

8 0
3 years ago
Consider equation of circle x2-2x+y2-4y-4=0,if line 2x-y+a=0 is its diameter then find value of a
g100num [7]

Answer:

Step-by-step explanation:

x² - 2x + y² - 4y - 4 = 0

x² - 2x + y² - 4y = 4

complete the squares

(x² - 2x + x₀) + (y² - 4y + y₀) = 4

the unknown number will be the square of half of the x¹ coefficient

(x² - 2x + 1) + (y² - 4y + 4) = 4 + 1 + 4

(x - 1)² + (y - 2)² = 9

This tells us that the circle is centered on (1, 2)

Which is also a point on the diameter

2x - y + a = 0

a = y - 2x

a = 2 - 2(1)

a = 0

4 0
3 years ago
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