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AVprozaik [17]
3 years ago
5

A right rectangular prism has a length of 10 centimeters, a width of 2.5 centimeters and a height of 0.9 centimeters what is the

wolume of the rectangular prism?
Mathematics
1 answer:
nikdorinn [45]3 years ago
7 0

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{22.5 \:  {cm}^{3} }}}}}

Step-by-step explanation:

Given,

Length of a rectangular prism ( l ) = 10 cm

Width of a rectangular prism ( w ) = 2.5 cm

Height of a rectangular prism ( h ) = 0.9 cm

Volume of a rectangular prism ( V ) = ?

<u>Finding </u><u>the</u><u> </u><u>volume</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectang</u><u>ular</u><u> </u><u>prism</u>

\boxed{ \bold{ \sf{volume \: of \: a \: rectangular \: prism = lwh}}}

\dashrightarrow{ \sf{volume = 10 \times 2.5 \times 0.9}}

\dashrightarrow{ \sf{volume = 22.5 \:  {cm}^{3} }}

Hope I helped!

Best regards! :D

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The monthly worldwide average number of airplane crashes of commercial airlines is 3.5. What is the probabil- ity that there wil
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Answer:

Step-by-step explanation:

We would apply the formula for poisson distribution which is expressed as

P(x = r) = (e^- µ × µ^r)/r!

Where

µ represents the mean of the theoretical distribution.

r represents the number of successes of the event.

From the information given,

µ = 3.5

a)

For the probability that there will be at least 2 such accidents in the next month, it is expressed as

P(x ≥ 2) = 1 - P(x < 2)

P(x < 2) = P(x = 0) + P(x = 1)

Therefore,

P(x = 0) = (e^- 3.5 × 3.5^0)/0!

P(x = 0) = (e^- 3.5 × 1)/1

P(x = 0) = 0.03

P(x = 1) = (e^- 3.5 × 3.5^1)/1!

P(x = 1) = (e^- 3.5 × 3.5)/1

P(x = 1) = 0.11

P(x < 2) = P(x = 0) + P(x = 1) = 0.03 + 0.11 = 0.14

P(x ≥ 2) = 1 - 0.14 = 0.86

b)

For the probability that there will be at most 1 accident in the next month, it is expressed as

P(x ≤ 1) = P(x = 0) + P(x = 1)

P(x = 0) = 0.03

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The number of people arriving at a ballpark is random, with a Poisson distributed arrival. If the mean number of arrivals is 10,
Stella [2.4K]

Answer:

a) 3.47% probability that there will be exactly 15 arrivals.

b) 58.31% probability that there are no more than 10 arrivals.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

If the mean number of arrivals is 10

This means that \mu = 10

(a) that there will be exactly 15 arrivals?

This is P(X = 15). So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 15) = \frac{e^{-10}*(10)^{15}}{(15)!} = 0.0347

3.47% probability that there will be exactly 15 arrivals.

(b) no more than 10 arrivals?

This is P(X \leq 10)

P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-10}*(10)^{0}}{(0)!} = 0.000045

P(X = 1) = \frac{e^{-10}*(10)^{1}}{(1)!} = 0.00045

P(X = 2) = \frac{e^{-10}*(10)^{2}}{(2)!} = 0.0023

P(X = 3) = \frac{e^{-10}*(10)^{3}}{(3)!} = 0.0076

P(X = 4) = \frac{e^{-10}*(10)^{4}}{(4)!} = 0.0189

P(X = 5) = \frac{e^{-10}*(10)^{5}}{(5)!} = 0.0378

P(X = 6) = \frac{e^{-10}*(10)^{6}}{(6)!} = 0.0631

P(X = 7) = \frac{e^{-10}*(10)^{7}}{(7)!} = 0.0901

P(X = 8) = \frac{e^{-10}*(10)^{8}}{(8)!} = 0.1126

P(X = 9) = \frac{e^{-10}*(10)^{9}}{(9)!} = 0.1251

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58.31% probability that there are no more than 10 arrivals.

8 0
3 years ago
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Step-by-step explanation:

-6 = 2/9 x

2/9x = -6

x = (-6)×9/2

= -27

4 0
3 years ago
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