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trasher [3.6K]
3 years ago
15

Find k so that the three equations 3x-y=2, 2x+8=3y, and y=kx have a common solution

Mathematics
1 answer:
andriy [413]3 years ago
8 0
2x+8=3kx (3k-2)x+8=0
3x-kx=2. (3-k)x-2=0
3k-2)x+10=3-k)x
4k-5=10/x
///////
3x-y-2=2x+8-3y
X+2y-10=0
X+2kx-10=0
K=(10-x)/2x
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Solve x42=37 x 42 = 3 7 using two different strategies. Explain each strategy.
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Given equation : \frac{x}{42}=\frac{3}{7}.

Strategy 1: We can cross mutiply both sides remove fraction form.

On cross multiplication, we get

x * 7 = 3 * 42

7x = 126.

Dividing both sides by 7, we get

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Strategy 2: We can find least common denominator(lcd) of both sides and multiplying both sides by that lcd to get rid denominators from both sides.

LCD of 42 and 7 is 42.

Therefore, multiplying both sides by 42, we get

42\times \frac{x}{42}=42\times\frac{3}{7}

x = 6 * 3

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1 year ago
You are studying for your final exam of the semester. up to this point, you received 3 exam scores of 67%, 68%, and 78℅. to rece
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Answer:

No it shouldent

Step-by-step explanation:

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