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trasher [3.6K]
4 years ago
15

Find k so that the three equations 3x-y=2, 2x+8=3y, and y=kx have a common solution

Mathematics
1 answer:
andriy [413]4 years ago
8 0
2x+8=3kx (3k-2)x+8=0
3x-kx=2. (3-k)x-2=0
3k-2)x+10=3-k)x
4k-5=10/x
///////
3x-y-2=2x+8-3y
X+2y-10=0
X+2kx-10=0
K=(10-x)/2x
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katrin [286]

Answer:

8.6%

Step-by-step explanation:

To find the percent change, you will need to compute the positive difference and then divide the difference by the original (the older amount).

So the positive difference will be obtain by doing larger minus smaller:

 6300

- 5800

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The older amount was 5800.

So 500/5800 is the answer as a un-reduced fraction.

I'm going to reduce it by dividing top and bottom by 100:

500/5800  = 5/58

5/58 is the answer as a reduced fraction.

5 divided by 58 gives=0.086206897  in the calculator .

Approximately 0.0862 is the answer as a decimal.

To convert this to a percentage, multiply it by a 100:

8.62%

Rounded to the nearest tenths is 8.6%

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So 5800+5800(.0862) should be pretty close to 6300 (not exactly though since we rounded).

5800+5800(.0862)=6299.96 using the calculator.

8 0
3 years ago
Find f(x) and g(x) so that the function can be described as y = f(g(x)). <br><br> y = 7/sqrt 8x +10
Blizzard [7]
Assuming you meant

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4 years ago
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4 years ago
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mash [69]

Answer:

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3 years ago
17/10 - 2/5 = *<br> Helpppp
uysha [10]
17/10-(2/5x2/2)
17/10-4/10
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