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3 years ago

15

If the area of a rectangle is 24a2b and the length is 8ab2, what would be the width of the rectangle, given that width is found

by dividing area by length? Simplify the answer

1 answer:

Goshia [24]3 years ago

5 0

(24ba^2)/(8ab^2)=3a/b=width

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Find the area under the curve y = 27/x3 from x = 1 to x = t. Evaluate the area under this curve for t = 10, t = 100, and t = 100

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Answer:

Step-by-step explanation:

given is a function as

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The curve from x=1 lies in the I quadratnt.

So area above x axis is to be calculated

Area = $\int\limits^t_1 {\frac{27}{x^3} } \, dx \\=\frac{-27}{2x^2} \\= \frac{-27}{2t^2}-\frac{-27}{2}\\=\frac{27}{2}(1-\frac{1}{t^2} )$

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