A TV with marked price Rs.16000 is available on 15% off. Then its selling price is

According to the University of Nevada Center for Logistics Management, 6% of all mer-

Fudgin [204]

Answer:

a) The point estimate of the proportion of items returned for the population of

sales transactions at the Houston store = 12/80 = 0.15

b) The 95% confidence interval for the proportion of returns at the Houston store = [0.0718 < p < 0.2282].

c) Yes.

We set an hypothesis and construct a test statistics. The test statistics result gives us:

Z calculated = 2.2545, and this gives us the p-value = 0.0121. We assumed 95% confident interval. Hence, the level of significance (α) = 5%. Conclusively, since the p-value ==> 0.0121 is less than (α) = 5%, the test is significant. Hence, the proportion of returns at the Houston store is significantly different from the returns for the nation as a whole.

Step-by-step explanation:

a) Point estimate of the proportion = number of returned items/ total items sold = 12/80 = 0.15.

b) By formula of confident interval:

CI(95%) = p ± Z* $\sqrt{\frac{p*(1-p)}{n} } = 0.15 \pm 1.96 *\sqrt{\frac{0.15*(1-0.15)}{80} }$ ,

CI(95%) = [0.0718 < p < 0.2282]

c) The hypothesis:

$H_{0}$ : The proportion of returns at the Houston store is not significantly different from the returns for the nation as a whole.

$H_{a}$ : The proportion of returns at the Houston store is significantly different from the returns for the nation as a whole.

The test statistics:

Z = $\frac{\hat{p} - p_{0}}{\sqrt{\frac{p*(1-p)}{n} }}$ , where $p_{0}$ is the proportion of nation returns.

Z calculated = 2.2545, and this gives us the p-value = 0.0121. We assumed 95% confident interval. Hence, the level of significance (α) = 5%. Conclusively, since the p-value ==> 0.0121 is less than (α) = 5%, the test is significant. Hence, the proportion of returns at the Houston store is significantly different from the returns for the nation as a whole.

6 0

3 years ago

The length of the segment indicated round your answer to the nearest 10th if nessesary

exis [7]

Pythagorean Theorem
x^2 = 15.7^2 -7.8^2
x^2 = 185.65 
x = 13.6253440324 
Answer is C

3 0

3 years ago

HELPPP PLEASEEE FOR 15POINTS

lilavasa [31]

Answer:

I'm not ok. that is too expensive

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

L || m

Alona [7]

Answer:

c. m∠1 + m∠6 = m∠4 + m∠6

Step-by-step explanation:

Given: The lines l and m are parallel lines.

The parallel lines cut two transverse lines. Here we can use the properties of transverse and find the incorrect statements.

a. m∠1 + m∠2 = m∠3 + m∠4

Here m∠1 and m∠2 are supplementary angles add upto 180 degrees.

m∠3 and m∠4 are supplementary angles add upto 180 degrees.

Therefore, the statement is true.

b. m∠1 + m∠5 = m∠3 + m∠4

m∠1 + m∠5 = 180 same side of the adjacent angles.

m∠3 + m∠4 = 180, supplementary angles add upto 180 degrees.

Therefore, the statement is true.

Now let's check c.

m∠1 + m∠6 = m∠4 + m∠6

We can cancel out m∠6, we get

m∠1 = m∠4 which is not true

Now let's check d.

m∠3 + m∠4 = m∠7 + m∠4

We can cancel out m∠4, we get

m∠3 = m∠7, alternative interior angles are equal.

It is true.

Therefore, answer is c. m∠1 + m∠6 = m∠4 + m∠6

3 0

3 years ago

Two percent of the customers of a store buy cigars. Half of the customers who buy cigars buy beer. 25 percent who buy beer buy c

enyata [817]

Answer:

0.95

Step-by-step explanation:

The computation of the probability that a customer neither buys beer nor buys cigars is given below;

Given that, the probabilities are

The customers who purchased cigars be 0.02

The customers who purchased cigars + beer 0.50

And, the customers who purchased beer + cigars be 0.25

Now the probabilities where the customer purchased both

= 0.05 × 0.02

= 0.10

The probability where the customer purchased beer is

= 0.01 ÷ 0.25

= 0.04

Now the probability where a customer neither buys beer nor buys cigars is

= 1 - 0.02 + 0.04 - 0.01

= 0.95

4 0

3 years ago