Given:
a varies jointly as b and c.
a=6 when b=2 and a=3.
To find:
The variation constant and the equation of variation.
Solution:
a varies jointly as b and c.
...(i)
Where, k is the constant of proportionality.
a=6 when b=2 and a=3.
The value of k is 1.
Putting k=1 in (i), we get
Therefore, the variation constant is 1 and the equation of variation is .
Answer:
21
Step-by-step explanation:
To find the answer, you'd have to continue tracing the diagonal line until it intersects with the vertical line that corresponds to the number 3.
If you do that, you'll see that in3 boxes, there are 21 footbals.
You can also calculate it mathematically:
If you have 7 balls per box as shown in the graph, you just have to multiply 7 by 3 to know how many balls you'll find in 3 boxes. 7 * 3 = 21.
Hope it helped,
BioTeacher101
Answer:
i dont know
Step-by-step explanation:
Answer:
9,0 0,9 -9,0 0,-9
Step-by-step explanation:
up down left right
The sum of the 8 terms of the series 1-1-3-5- ... -13 is -48
The given sequence is:
1,-1,-3, . . -13
and there are 8 terms.
The related series of this sequence is:
1-1-3-5- ... -13
Notice that the series is an arithmetic series with:
first term, a(1) = 1
common difference, d = -1 - (1) = -2
last term, a(8) = -13
To find the sum of the series, use the sum formula:
S(n) = n/2 [(a(1) + a(n)]
Substitute n = 8, a(1) = 1, a(n) = a(8) = -13 into the formula:
S(8) = 8/2 [1 + (-13)]
S(9) = 4 . (-12) = -48
Learn more about sum of a series here:
brainly.com/question/14203928
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