10%= 8
5% = 4
or 0.05 x 80 = 4
Assuming that you're talking about a standard deck of 52 cards, there are 4 tens and 4 aces.
So, at the beginning, you have probability 4/52=1/13 to draw a ten.
You replace, and you have an identical probability to draw an ace (you still have 4 favourable cases over 52 total cases).
Multiply the two probabilities to find the answer:

Answer:
See below
Step-by-step explanation:
- Initial Principal P₀ = 1000
- End of first period = 1000 + 1000*0.02/4 = 1005
- End of second period = 1005 + 1000*0.02/4 = 1010
- End of third period = 1010 + 1000*0.02/4 = 1015
- End of fourth period = 1015 + 1000*0.02/4 = 1020
Answer:
B. (-9,-17/4)
A.(-7/2.11/2)
I'm not sure if this is what you're looking for, but it's what I got.
Step-by-step explanation:
my best guess is (-1,1) (-1,2) (-2,3), i just drew a line graph and plotted the points and connected where the x axis lines meet