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nata0808 [166]
3 years ago
9

Two airplanes leave an airport at the same time. One airplane travels at 400 km/h

Mathematics
1 answer:
Neko [114]3 years ago
4 0

Answer:

912.414

Step-by-step explanation:

The angle

θ

between the directions of motion of planes

θ

=

320

−

200

=

120

∘

The distance

a

traveled by first plane flying at a speed of

150

km/hr

in

3

hrs

a

=

150

⋅

3

=

450

k

m

Similarly, the distance

b

traveled by second plane flying at a speed of

200

km/hr

in

3

hrs

b=

200x3=

600 km

Now, the distance between the planes after 3

hrs will be equal to the side of a triangle opposite to the angle θ=120∘

included by the sides

a

=

450

& b=

600

.

Now, using Cosine rule in the concerned triangle, the distance between the plane after

3

hours is given as

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