Ok so for part A, the x-coordinate of the intersection is the solution to <span><span>2<span>−x</span></span>=<span>4<span>x+3.
Part B </span></span></span><span>y>3x+10</span> for (8,10)
<span><span><span>10>3(8)+10</span><span>10>34
I am not sure about the thrid one
</span></span></span>
13. 12 3/8
14. 9 2/3
15. 3 4/10
16. 3
Answer:
Correct answer: B
Step-by-step explanation:
Syntax: in piecewise functions such as the one attached, the "if:" section shows the domain, or x-axis values which that function pertains to.
In the graph, you can see that the graph is defined for 
(not-including 1 because there is an open hole there, indicating it is not part of the domain), and 
.
Now that we know the domain, we can attach it to the graphs that lie on those domains.
We see that the leftmost line appears to have a positive slope and a negative y-intercept, and that the second line should have a positive y-intercept and a negative slope.
At this point, you can just start crossing off answers that don't meet this criteria.
Cheers!!
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Slope :
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y = -5x + 2
Slope = -5
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y - intercept :
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At (0. 3), y-intercept = 3
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Equation :
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y = mx + b
y = -5x + 3
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Answer : y = -5 + 3
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That's a quadratic, a nice parabola in vertex form.
The parabola has a positive x^2 term, so it's a CUP, concave up positive. It will have a minimum at the vertex, which is (2,5). Plot that point.
Now we need a couple of guide points to draw the usual parabola going up from both sides of its vertex. We try x=0 giving (0,9) and see that x=4 also gives 9, (4,9). Plot the parabola through those two points and the vertex and you're done.
