If you let j, c, t represent the prices of jeans, camisoles, and t-shirts, respectively, the three purchases can be described by ...
2j +2c +4t = 90.00
1j +0c +3t = 42.50
1j +3c +2t = 62.00
It is convenient to let a calculator solve these equations. It can tell you the row-reduced matrix equations are ...
[[1 0 0 24.5]
[0 1 0 8.5 ]
[0 0 1 6 ]]
which means
flare jeans cost $24.50
camisoles cost $8.50
T-shirts cost $6.00
Solve for X on both equations
2x - 2 < -12
Add two on both sides
2x < -10
Divide by two on both sides
2 < -5
2x + 3 > 7
Subtract three on both sides
2x > 4
Divide by two on both sides
x > 2
A. x < -5 or x > 2
Answer:
4.5
Step-by-step explanation:
Step-by-step explanation:
(a) 3pq / 4r² × 2rs / 6q²......first start by expanding the expression
It will be ;
3 × p × q / 4 × r × r X 2 × r × s / 6 × q × q
so now ,cancel out like terms. The q on top can cancel out with the q down same thing happens to r
so you'll get something like ;
3 × q / 4 × r X 2 × s / 6 × q ......so now divide , like 3 into 6 and 2 into 4 ,then you'll get something like;
qs / 4q
that's the answer
(b)15 ab² / 8 c²d ÷ 3ab / 4cd.......start by changing the sign from ÷ to × and then 3ab and 4cd will switch places
15ab² / 8c² d × 4cd / 3ab.....expand the expression
15 ×a×b×b / 8×c×c×d X 4×c×d / 3×a×b
then cancel like terms and you'll get;
15b / 8c X 4/3.....then divide 3 into 15 and 4 into 8
5b / 2c
hope this helps
Answer:
![y = e^{3x}.cos4x.sin2x](https://tex.z-dn.net/?f=y%20%3D%20e%5E%7B3x%7D.cos4x.sin2x)
![=> y' =- 3e^{3x}.4sin4x.2cos2x=-24.e^{3x}.sin4x.cos2x](https://tex.z-dn.net/?f=%3D%3E%20y%27%20%3D-%203e%5E%7B3x%7D.4sin4x.2cos2x%3D-24.e%5E%7B3x%7D.sin4x.cos2x)
![dy=y'.dx => dy = -24e^{3x}.sin4x.cos2x.dx](https://tex.z-dn.net/?f=dy%3Dy%27.dx%20%3D%3E%20dy%20%3D%20-24e%5E%7B3x%7D.sin4x.cos2x.dx)
Step-by-step explanation: