The given plane,
, has normal vector
. Any plane parallel to this one has the same normal vector.
Let
be any point in the plane we want. The plane contains the point (1, 1, -1), so an arbitrary vector in this plane is

and this is perpendicular to
.
So the equation of the plane is

or equivalently,

Answer:
-2/5, -1/2, -1, -4/3
Step-by-step explanation:
Doing this so I can ask sorry
Answer:<
Step-by-step explanation: