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3 years ago

5

Review:

1 answer:

alex41 [277]3 years ago

7 0

Answer:

Step-by-step explanation:

Well 6 to the second power is when you multiply 6 x 6 = 36

And ab= -320

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How can I simplify 9a + 10(6a - 1) as an expression

Elodia [21]

Answer:

69a-10

Step-by-step explanation:

7 0

3 years ago

A quantity P is an exponential function of time I, such that P = 160 when t = 6 and P = 150 when I = 4. Use the given informatio

Klio2033 [76]

Answer:

k = 0.032
P0 = 131.836

Step-by-step explanation:

Perhaps you want to use the points (t, P) = (4, 150) and (6, 160) to find the parameters P0 and k in the equation ...

$P(t)=P_0\cdot e^{kt}$

We know from the given points that we can write the equation as ...

$P(t)=150\left(\dfrac{160}{150}\right)^{(t-4)/(6-4)}=150\left(\dfrac{16}{15}\right)^{\frac{t}{2}-2}\\\\=150\left(\dfrac{16}{15}\right)^{-2}\times\left(\left(\dfrac{16}{15}\right)^{\frac{1}{2}}\right)^t$

Comparing this to the desired form, we see that ...

$P_0=150\left(\dfrac{16}{15}\right)^{-2}\approx 131.836\\\\e^{k}=\left(\dfrac{16}{15}\right)^{1/2}\rightarrow k=\dfrac{1}{2}(\ln{16}-\ln{15})\approx 0.0322693$

So, the approximate equation for P is ...

$P(t)=131.836\cdote^{0.032t}$

And the parameters of interest are ...

k = 0.032
P0 = 131.836

4 0

3 years ago

Find the midpoint of the line segment with the endpoints A and B.<br> A(10,6); B(8,4)

MatroZZZ [7]

Answer:

(9,5)

Step-by-step explanation:

10+8/2=18/2=9

6+4/2=10/2=5

4 0

3 years ago

The peters creek restaurant has an all you can eat shrimp deal

deff fn [24]

Huh i don’t get it sorry

6 0

3 years ago

What is factorisation

liubo4ka [24]

Factorization is a method of writing numbers as the product of their factors or divisors.

<em><u>Solution:</u></em>

<em><u>Factorisation:</u></em>

Factorization is a method of writing numbers as the product of their factors or divisors.

In other words we can say, Finding what to multiply together to get an expression.

It is like "splitting" an expression into a multiplication of simpler expressions.

<em><u>Methods of factorisation:</u></em>

Factoring out the GCF

The sum-product pattern

The grouping method

The perfect square trinomial pattern

The difference of squares pattern

<em><u>Factoring out the GCF:</u></em>

This methods means that factoring out common factors

For example:

$12x^2 + 3x = 3x(4x + 1)$

This can be used when each term in given expression shares a common factor

<em><u>The sum-product pattern</u></em>

A quadratic equation may be expressed as a product of two binomials

For example:

$x^2 + 7x + 12 = (x + 3)(x + 4)$

This method can be used for quadratic equations of form $ax^2 + bx + c = 0$

<em><u>The grouping method</u></em>

If the polynomial is of the form $ax^2 + bx + c$ and there are factors of ac that add up to b , we can use this method

For example:

$2x^2 + 7x + 3\\\\2x^2 + 6x + 1x + 3\\\\2x(x + 3) + 1(x + 3)\\\\(x + 3)(2x + 1)$

<em><u>The perfect square trinomial pattern</u></em>

If the first and last terms are perfect squares and the middle term is twice the product of their square roots , we can use this method

For example:

$x^2 + 10x + 25\\\\(x + 5)^2$

<em><u>The difference of squares pattern</u></em>

If the expression represents a difference of squares, we can use this method

Because $a^2 - b^2 = (a + b)(a - b)$

For example:

$x^2 - 25\\\\x^2 - 5^2\\\\(x + 5)(x - 5)$

6 0

3 years ago