log₉(<em>x</em> - 7) + log₉(<em>x</em> - 7) = 1
2 log₉(<em>x</em> - 7) = 1
log₉(<em>x</em> - 7) = 1/2
Take the base-9 antilogarithm of both sides; in other words, make both sides powers of 9:
can also be written as √9 = 3, and , so the equation reduces to
<em>x</em> - 7 = 3
Solve for <em>x</em> :
<em>x</em> = 10
Hi there!
• g(x) = 6x - 3
Then,
if g(x) = y :-
y = 6x - 3
⇒6x = y + 3
⇒x =
According to th' question :-
g⁻¹(x) =
g⁻¹(9) =
g⁻¹(9) =
g⁻¹(9) = 2
Hence,
The required answer is g⁻¹(9) = 2
~ Hope it helps!
Answer:
70 kg
Step-by-step explanation: