Assuming that you want to add or subtract them and want the bottom number the same,
1/4 and 2/3
least common multiple of 4 and 3
4=2 times 2
3=3 times 1
so the leas common mulltiple will include all of them
the number is 2 times 2 times 3 or 12
lcm=12
1/4 times 3/3=3/12
2/3 times 4/4=8/12
add or subtract 3 and 8
LCM=12
You have to find first the discriminant
∆=8^2-4*(-1) *(-7) =36
x=(-8±√36) /-2=(-8±6)/-2=4±3=1 or 7
So x(1)=1 or x(2)=7
-x^2+8x-7=[x-x(1) ][x-x(2) ]=(x-1) (x-7)
9514 1404 393
Answer:
The (piece, perceived values) are ...
- Cindy, (3, 48%)
- Jamal, (1, 39%)
- Monique, (2, 33%)
Step-by-step explanation:
We assume the values and questions are as shown in the attachment.
1. After the division, Cindy bids only on piece 3, and Jamal bids only on piece 1. Hence the appropriate final division is ...
Cindy: piece 3
Jamal: piece 1
Monique: piece 2
__
2. Monique divides the land so that the value of each piece to her is 33 1/3%. That is her perceived value for the piece she gets.







The absolute value of a real number a is a when a≥0, or -a when a<0. The absolute value of -6 is 6. The absolute value of 4 is 4.
#IfWrongPleaseReport
#StudyTogetherWithMe
#ILoveMath