Hello there,
Alright so first we should write down what do we already know based on the problem:
- 1st day she practiced 3/8 hours
- 2nd day she practiced 1 1/4 hours
- 3rd day she practiced 2 1/8 hours
- she increased the time each day by the same amount
Now in order to solve the problem we first need to figure out by how much did she increase her practice time...
we would need to subtract day 2 practice from day 1
- 1 1/4 as an improper fraction is 5/4
- 5/4 written with a common denominator would be 10/8
- 10/8 - 3/8 = 7/8
So the common difference between the two days was 7/8 hours, that how much she increased from day 1 to day 2. Now in order to make sure that the difference among the tree is the same we would need to subtract day 3 by day 2...
- 2 1/8 as an improper fraction is 17/8
- 17/8 - 10/8 is 7/8
So yes the difference is 7/8 hours increased each day. Now we need find out how much she practiced on the FIFTH day.
- we add 7/8 with 7/8, since we last stopped at day 3
- we add 14/8 to 17/8 which would be 31/8 hours
- change 31/8 into a mixed number would be 3 7/8 hours
On the fifth day Kendra would practice for 3 7/8 hours.
Hope I helped,
Amna
Answer:
i believe its 10 newtons to the left
Step-by-step explanation:
im sorry if this is wrong
2a) if 1 ft³ weighs 150 lb==>the TOTAL VOLUME =5,000/150 =33.334 ft³
2b) 1 ft³ 1,728 in³. So the TOTAL volume in in³ =33.334 x 1728 = 57,600 in³
c) Volume =(1/3)(πR²).H but R = H then V= (1/3)(πR³).plug V (=57600)
57,600 = 1/3 (πR³) ==> R³ = (3 x 57600) / π ==> R = 38 in
d) Area x thickness = Volume ==> Area x 2 in = 57600 in then:
Are =57600/2 & Area =28,800 in²