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bazaltina [42]
3 years ago
9

Explain how to use a graph of the function f(x) to find f(3).

Mathematics
2 answers:
saw5 [17]3 years ago
4 0

Answer:

You would plug in the number 3 into both the F(x) and the x of the equation. By solving for x of your new equation, you would be able to find the value of f(3)!

Step-by-step explanation:

Minchanka [31]3 years ago
3 0

Answer:

You plug in the number 3 into both the f(x) and the x of the equation. By solving for x of the equation, you would find f(3).

It'd look something like this:

we know that x = 3

f(x) = whatever the function is (say x^3 + 3x^2 + 5x + 1)

f(3) = 3^3 + 3 * 3^2 + 5 * 3 + 1

= 27 + 9 + 15 + 1

= 52

Hope this helps, and please mark me brainliest if it does!

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What are the solutions to the equation |x-3|=14
lilavasa [31]
X-3=14
+3    +3
x=17


x-3=-14
  +3   +3
x=-11
5 0
3 years ago
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Can someone please explain step by step on how I can get the answer? If so I’ll mark you brainliest
krok68 [10]

Answer:

3

Step-by-step explanation:

18 factors to 2, 3, 3

45 factors down to 5,3,3

6 0
3 years ago
A coin is flipped five times. Find the number of possible sets of heads and tails that have 0 heads.
Fudgin [204]

Answer:

I think it’s C

Step-by-step explanation:

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3 years ago
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What are the real and complex solutions of the polynomial equation? x^4-41x^2=-400. *work needed*
pickupchik [31]
<h3>Answer: x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>

Step-by-step explanation:

Given the polynomial equation x^4-41x^2=-400.

Adding 400 on both sides to get rid 400 from right side and set 0 on right side, we get

x^4-41x^2+400=-400+400.

x^4-41x^2+400=0.

Factoring by product sum rule.

We need product of 400 and sum upto -41.

We can see that 400 = -25 × -16 = 400 and -25-16 = -41.

Therefore,

x^4-25x^2-16x^2+400=0

Making it into two groups, we get

(x^4-25x^2)+(-16x^2+400)=0

Factoring out GCF of each group, we get

x^2(x^2-25)-16(x^2-25)=0

(x^2-25)(x^2-16) =0

Factoring out  (x^2-25) and (x^2-16) separately by difference of the squares identity a^2-b^2=(a-b)(a+b), we get

(x^2-25) = x^2-5^2= (x-5)(x+5) and

x^2-16 = x^2-4^2 =(x-4)(x+4).

Therefore,

(x-5)(x+5)(x-4)(x+4) =0

Applying zero product rule,

x-5=0

x+5=0

x-4=0 and

x+4=0.

Therefore,

<h3>x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>
6 0
3 years ago
Mr. Johns gave a test last week and Ginny missed one question. She answered that 14.5 people would ride on each bus rather than
Mars2501 [29]

Mr. Johns handle this situation to Agree to meet, listen to their concerns, and then explaining that one component of math is understanding reasonable answers.

Mr. Johns gave a test last week and Ginny missed one question. She answered that 14.5 people would ride on each bus rather than 15. Her parents would like a conference because she did the math problem correctly and should receive credit even though her answer was not reasonable.

Mr. Johns handle this situation to Agree to meet, listen to their concerns, and then explain that one component of math is understanding reasonable answers.

Learn more about  the reasoning here brainly.com/question/25175983

#SPJ4

4 0
2 years ago
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